Php MySQLi不会在pthreads工作线程中建立连接

为什么在PHP中使用时不能创建连接？当建立mysqli并尝试执行查询时，将生成一个错误

PHP警告：mysqli:：query（）：无法在中获取mysqli 第47行W:\workspace\Sandbox\application.php

这是我的

---

以下是一些工作代码

<?php

class SQLWorker extends Worker {

    public function __construct($hostname, $username, $password, $database, $port = 3306) {
        $this->hostname = $hostname;
        $this->username = $username;
        $this->password = $password;
        $this->database = $database;
    }

    public function run() {
        /* the static class scope acts as a kind of thread local storage for this class */
        self::$connection = new MySQLi
            ($this->hostname, $this->username, $this->password, $this->port);
    }

    public function getConnection() {
        return self::$connection;
    }

    protected $hostname;
    protected $username;
    protected $password;
    protected $database;
    protected $port;

    protected static $connection;
}

class SQLTask extends Threaded {
    public function __construct($sql) {
        $this->sql = $sql;
    }

    public function run() {
        /* fetch static (thread local) connection */
        $link = $this->worker->getConnection();

        if ($link) {
            /* execute query, keep result in local scope */
            $result = $link->query($this->sql);

            /* build up results as normal array */
            while (($row = $result->fetch_assoc())) {
                $rows[] = $row;
            }
        }

        /* store results in a fetchable form */
        $this->rows = $rows;
    }

    public function getResults() {
        return $this->rows;
    }
}

$pool = new Pool(4, 
    SQLWorker::class, 
    ["localhost", "username", "password", "database"]);

$pool->submit(
    $task = new SQLTask("SELECT 1"));

$pool->shutdown();

/* you have your normal array of data here */
var_dump($task->getResults());

第81行是什么？在我的编辑器中是一个空行。@Fred ii-见第47行。我对主题中的脚本做了一些更改。删除了不必要的评论等。您使用的是什么版本的PHP？@Fred ii-PHP5.5.12（cli）（构建时间：2014年4月30日11:20:55）对不起，我不能聊天，我得走了。我会+1看看是否有人能理解。乔，谢谢你。这种线程化对象行为是否会导致实例级对象的丢失？（参见问题中另一位出资人的例子，以及我在回答中的一位。）啊哈，你已经成功了。似乎有两种解决方案-一种是在
工作者
内部创建数组/对象
静态
，另一种是使用扩展
可堆叠的对象
。后者的目的只是为了防止并发线程同时修改共享资源吗？
<?php

class SQLWorker extends Worker {

    public function __construct($hostname, $username, $password, $database, $port = 3306) {
        $this->hostname = $hostname;
        $this->username = $username;
        $this->password = $password;
        $this->database = $database;
    }

    public function run() {
        /* the static class scope acts as a kind of thread local storage for this class */
        self::$connection = new MySQLi
            ($this->hostname, $this->username, $this->password, $this->port);
    }

    public function getConnection() {
        return self::$connection;
    }

    protected $hostname;
    protected $username;
    protected $password;
    protected $database;
    protected $port;

    protected static $connection;
}

class SQLTask extends Threaded {
    public function __construct($sql) {
        $this->sql = $sql;
    }

    public function run() {
        /* fetch static (thread local) connection */
        $link = $this->worker->getConnection();

        if ($link) {
            /* execute query, keep result in local scope */
            $result = $link->query($this->sql);

            /* build up results as normal array */
            while (($row = $result->fetch_assoc())) {
                $rows[] = $row;
            }
        }

        /* store results in a fetchable form */
        $this->rows = $rows;
    }

    public function getResults() {
        return $this->rows;
    }
}

$pool = new Pool(4, 
    SQLWorker::class, 
    ["localhost", "username", "password", "database"]);

$pool->submit(
    $task = new SQLTask("SELECT 1"));

$pool->shutdown();

/* you have your normal array of data here */
var_dump($task->getResults());