Php 如何通过真实类调用非上下文场景中的mockry

鉴于这一类别：

MyClass
{   
    public function getValueFrom($foo)
    {
        return 'data';
    }
}

我想用特定参数测试对函数

getValueFrom

的特定调用：

$mock = Mockery::mock(MyClass);
$mock->shouldReceive('getValueFrom')
    ->with('foo')
    ->once()
    ->andReturn('bar');

(new MyClass)->foo('foo'); // returns bar
(new MyClass)->foo('someting-else'); // throws Mockery\Exception\NoMatchingExpectationException

如果我使用不同于“foo”的参数调用同一个方法，它将抛出NoMatchingExpectationException。如何将非上下文场景委托给真实类？令人担忧的行为是：

$mock = Mockery::mock(MyClass);
$mock->shouldReceive('getValueFrom')
    ->with('foo')
    ->once()
    ->andReturn('bar');

(new MyClass)->foo('foo'); // returns bar
(new MyClass)->foo('someting-else'); // return data
(new MyClass)->foo('anything-else'); // return data

---

为了防止评论错误，这将起到以下作用：

$mock = Mockery::mock(MyClass);
$mock->shouldReceive('getValueFrom')
    ->with('foo')
    ->once()
    ->andReturn('bar');

// here!!
$mock->shouldDeferMissing();

(new MyClass)->foo('foo'); // returns bar
(new MyClass)->foo('someting-else'); // return data
(new MyClass)->foo('anything-else'); // return data