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Php 避免重定向到同一页面后重新提交表单_Php_Forms_Post - Fatal编程技术网

Php 避免重定向到同一页面后重新提交表单

Php 避免重定向到同一页面后重新提交表单,php,forms,post,Php,Forms,Post,我在网上搜索了很多,但我还是很困惑。我有一个表格,我提交并重定向到它自己。然后,它将变量回显到屏幕上。但是,在用户点击刷新按钮后,如何防止表单重新提交??这是可以实现的吗?如何实现???这是密码 <!DOCTYPE HTML> <html> <head> </head> <body> <?php // de

我在网上搜索了很多,但我还是很困惑。我有一个表格,我提交并重定向到它自己。然后,它将变量回显到屏幕上。但是,在用户点击刷新按钮后,如何防止表单重新提交??这是可以实现的吗?如何实现???这是密码

            <!DOCTYPE HTML> 
        <html>
        <head>
        </head>
        <body> 

        <?php
        // define variables and set to empty values
        $name = $email = $gender = $comment = $website = "";

        if ($_SERVER["REQUEST_METHOD"] == "POST") {
           $name = test_input($_POST["name"]);
           $email = test_input($_POST["email"]);
           $website = test_input($_POST["website"]);
           $comment = test_input($_POST["comment"]);
           $gender = test_input($_POST["gender"]);
           echo "<h2>Your Input:</h2>";
        echo $name;
        echo "<br>";
        echo $email;
        echo "<br>";
        echo $website;
        echo "<br>";
        echo $comment;
        echo "<br>";
        echo $gender;
        }
        if($_SERVER["REQUEST_METHOD"] == "GET")
        {
            header('Location: '. $_SERVER['PHP_SELF'] , true, 303);
        }

        function test_input($data) {
           $data = trim($data);
           $data = stripslashes($data);
           $data = htmlspecialchars($data);
           return $data;
        }
        ?>

        <h2>PHP Form Validation Example</h2>
        <form method="post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>"> 
           Name: <input type="text" name="name">
           <br><br>
           E-mail: <input type="text" name="email">
           <br><br>
           Website: <input type="text" name="website">
           <br><br>
           Comment: <textarea name="comment" rows="5" cols="40"></textarea>
           <br><br>
           Gender:
           <input type="radio" name="gender" value="female">Female
           <input type="radio" name="gender" value="male">Male
           <br><br>
           <input type="submit" name="submit" value="Submit"> 
        </form>

PHP表单验证示例

简单地说,若存在post值,则不显示submit按钮或删除submit按钮的行为,如下所示

<form method="post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>"> 
       Name: <input type="text" name="name">
       <br><br>
       E-mail: <input type="text" name="email">
       <br><br>
       Website: <input type="text" name="website">
       <br><br>
       Comment: <textarea name="comment" rows="5" cols="40"></textarea>
       <br><br>
       Gender:
       <input type="radio" name="gender" value="female">Female
       <input type="radio" name="gender" value="male">Male
       <br><br>
       <?php if(!isset($_POST["name"])) { ?>
       <input type="submit" name="submit" value="Submit">
       <?php } ?>
    </form>

您应该停止这种奇怪的习惯,让表单提交到生成表单的脚本。我一直不明白为什么会这样做。它引起了很多问题。您有一个生成视图、表单的操作,还有一个处理表单的操作。所以有两个独立的脚本。简单、高效和透明。即使我停止提交相同的脚本,表单也会在页面刷新时继续重新提交。你能告诉我怎么停止吗??提交错误数据时,我应该如何向用户显示错误消息???