Php 如何使用mysqli\u fetch\u数组从MySQL列获取数组

我正试图写一个IP禁令。用户IP存储在数据库中。我可以手动将该用户IP添加到banlist。不幸的是，下面的代码不起作用。我认为问题在于将数组从数据库中取出

$ip = $_SERVER['REMOTE_ADDR'];
$bannedips = array();
$notBanned = true; //later used to check, if ip is banned

$sql = "SELECT ip FROM ipban";
$result = mysqli_query($conn, $result);
while($row = mysql_fetch_array($result, MYSQL_NUM)){
    $bannedips[] = $row;
}
if (in_array($ip, $bannedips)) {
    $notBanned = false;
}

只要改变一下：

while($row = mysql_fetch_array($result, MYSQL_NUM)){
    $bannedips[] = $row;

您不能将mysqli函数与mysql合并

$result = mysqli_query($conn, $result);
while($row = mysql_fetch_array($result, MYSQL_NUM)){

最后（编辑）：

您可以在以下网址阅读更多内容：

只要改变一下：

while($row = mysql_fetch_array($result, MYSQL_NUM)){
    $bannedips[] = $row;

您不能将mysqli函数与mysql合并

$result = mysqli_query($conn, $result);
while($row = mysql_fetch_array($result, MYSQL_NUM)){

最后（编辑）：

您可以在以下网址阅读更多内容：

只要改变一下：

while($row = mysql_fetch_array($result, MYSQL_NUM)){
    $bannedips[] = $row;

您不能将mysqli函数与mysql合并

$result = mysqli_query($conn, $result);
while($row = mysql_fetch_array($result, MYSQL_NUM)){

最后（编辑）：

您可以在以下网址阅读更多内容：

只要改变一下：

while($row = mysql_fetch_array($result, MYSQL_NUM)){
    $bannedips[] = $row;

您不能将mysqli函数与mysql合并

$result = mysqli_query($conn, $result);
while($row = mysql_fetch_array($result, MYSQL_NUM)){

最后（编辑）：

您可以在以下网址阅读更多内容：

---

问题在while循环中进行。在将数据附加到$bannedips数组时，您忘记了从$row数组中选择第0个（ip列）键

将$row更改为row[0]如下所示：

while($row = mysql_fetch_array($result, MYSQL_NUM)){
    $bannedips[] = $row[0];
}

---

问题在while循环中进行。在将数据附加到$bannedips数组时，您忘记了从$row数组中选择第0个（ip列）键

将$row更改为row[0]如下所示：

while($row = mysql_fetch_array($result, MYSQL_NUM)){
    $bannedips[] = $row[0];
}

---

问题在while循环中进行。在将数据附加到$bannedips数组时，您忘记了从$row数组中选择第0个（ip列）键

将$row更改为row[0]如下所示：

while($row = mysql_fetch_array($result, MYSQL_NUM)){
    $bannedips[] = $row[0];
}

---

问题在while循环中进行。在将数据附加到$bannedips数组时，您忘记了从$row数组中选择第0个（ip列）键

将$row更改为row[0]如下所示：

while($row = mysql_fetch_array($result, MYSQL_NUM)){
    $bannedips[] = $row[0];
}

---

由于性能原因，您不应该查询所有条目，而应该只搜索ip

$ip = $_SERVER['REMOTE_ADDR'];
$notBanned = true; //later used to check, if ip is banned

$sql = "SELECT ip FROM ipban WHERE ip = ?";
if ($stmt = mysqli_prepare($conn, $sql)) {
    /* bind parameters for markers */
    mysqli_stmt_bind_param($stmt, "s", $ip);

    if($result = mysqli_query($conn, $sql)){
        $notBanned = false;
        mysqli_free_result($result);
    }
}

面向对象的样式应为：

$mysqli = new mysqli(/* Whatever needed to establish connection */);
$ip = $_SERVER['REMOTE_ADDR'];
$notBanned = true; //later used to check, if ip is banned

$sql = "SELECT ip FROM ipban WHERE ip = ?";

if ($stmt = $mysqli->prepare($sql)){
    $stmt->bind_param("s", $ip);
    $stmt->execute();
    if($stmt && $stmt->num_rows > 0){
        $notBanned = false;
    }
}

---

由于性能原因，您不应该查询所有条目，而应该只搜索ip

$ip = $_SERVER['REMOTE_ADDR'];
$notBanned = true; //later used to check, if ip is banned

$sql = "SELECT ip FROM ipban WHERE ip = ?";
if ($stmt = mysqli_prepare($conn, $sql)) {
    /* bind parameters for markers */
    mysqli_stmt_bind_param($stmt, "s", $ip);

    if($result = mysqli_query($conn, $sql)){
        $notBanned = false;
        mysqli_free_result($result);
    }
}

面向对象的样式应为：

$mysqli = new mysqli(/* Whatever needed to establish connection */);
$ip = $_SERVER['REMOTE_ADDR'];
$notBanned = true; //later used to check, if ip is banned

$sql = "SELECT ip FROM ipban WHERE ip = ?";

if ($stmt = $mysqli->prepare($sql)){
    $stmt->bind_param("s", $ip);
    $stmt->execute();
    if($stmt && $stmt->num_rows > 0){
        $notBanned = false;
    }
}

---

由于性能原因，您不应该查询所有条目，而应该只搜索ip

$ip = $_SERVER['REMOTE_ADDR'];
$notBanned = true; //later used to check, if ip is banned

$sql = "SELECT ip FROM ipban WHERE ip = ?";
if ($stmt = mysqli_prepare($conn, $sql)) {
    /* bind parameters for markers */
    mysqli_stmt_bind_param($stmt, "s", $ip);

    if($result = mysqli_query($conn, $sql)){
        $notBanned = false;
        mysqli_free_result($result);
    }
}

面向对象的样式应为：

$mysqli = new mysqli(/* Whatever needed to establish connection */);
$ip = $_SERVER['REMOTE_ADDR'];
$notBanned = true; //later used to check, if ip is banned

$sql = "SELECT ip FROM ipban WHERE ip = ?";

if ($stmt = $mysqli->prepare($sql)){
    $stmt->bind_param("s", $ip);
    $stmt->execute();
    if($stmt && $stmt->num_rows > 0){
        $notBanned = false;
    }
}

---

由于性能原因，您不应该查询所有条目，而应该只搜索ip

$ip = $_SERVER['REMOTE_ADDR'];
$notBanned = true; //later used to check, if ip is banned

$sql = "SELECT ip FROM ipban WHERE ip = ?";
if ($stmt = mysqli_prepare($conn, $sql)) {
    /* bind parameters for markers */
    mysqli_stmt_bind_param($stmt, "s", $ip);

    if($result = mysqli_query($conn, $sql)){
        $notBanned = false;
        mysqli_free_result($result);
    }
}

面向对象的样式应为：

$mysqli = new mysqli(/* Whatever needed to establish connection */);
$ip = $_SERVER['REMOTE_ADDR'];
$notBanned = true; //later used to check, if ip is banned

$sql = "SELECT ip FROM ipban WHERE ip = ?";

if ($stmt = $mysqli->prepare($sql)){
    $stmt->bind_param("s", $ip);
    $stmt->execute();
    if($stmt && $stmt->num_rows > 0){
        $notBanned = false;
    }
}

---

$bannedips[]=$row['ip']

如果使用

MYSQL_NUM

-

$banndips[]=$row[0]

至少尝试打印变量以查看它们包含的内容。@SimonMathewson我根据您的要求编辑我的答案，请参见下面的

$banndips[]=$row['ip']

如果使用

MYSQL_NUM

-

$banndips[]=$row[0]

至少尝试打印变量以查看它们包含的内容。@SimonMathewson我根据您的要求编辑我的答案，请参见下面的

$banndips[]=$row['ip']

如果使用

MYSQL_NUM

-

$banndips[]=$row[0]

至少尝试打印变量以查看它们包含的内容。@SimonMathewson我根据您的要求编辑我的答案，请参见下面的

$banndips[]=$row['ip']

如果使用

MYSQL_NUM

-

$bannedips[]=$row[0]

至少尝试打印变量以查看它们包含的内容。@SimonMathewson我根据您的要求编辑我的答案，请参见下面的感谢！这看起来像是面向对象的mysqli吗？谢谢！这看起来像是面向对象的mysqli吗？谢谢！这看起来像是面向对象的mysqli吗？谢谢！这看起来像是面向对象的mysqli吗？还有其他错误：无法将mysqli函数与mysqli合并还有其他错误：无法将mysqli函数与mysqli合并还有其他错误：无法将mysqli函数与mysqli合并还有其他错误：无法将mysqli函数与mysql合并