Php 在发送id为行的新页面上显示单个条目
我对php和mysqli非常熟悉，并找到了一个很棒的教程，但我需要一些帮助 我希望一行是可链接的，并将其发送到另一个名为single.php？id=ROWID的页面，以便显示单个条目 这就是我目前得到的Php 在发送id为行的新页面上显示单个条目,php,mysqli,Php,Mysqli,我对php和mysqli非常熟悉，并找到了一个很棒的教程，但我需要一些帮助 我希望一行是可链接的，并将其发送到另一个名为single.php？id=ROWID的页面，以便显示单个条目 这就是我目前得到的 <html> <head> <title>MySQLi Tutorial</title> </head> <body> <?php //include database co
<html>
<head>
<title>MySQLi Tutorial</title>
</head>
<body>
<?php
//include database connection
include 'db_connect.php';
$action = isset($_GET['action']) ? $_GET['action'] : "";
if($action=='delete'){ //if the user clicked ok, run our delete query
$query = "DELETE FROM users WHERE id = ".$mysqli->real_escape_string($_GET['id'])."";
if( $mysqli->query($query) ){
echo "User was deleted.";
}else{
echo "Database Error: Unable to delete record.";
}
}
$query = "select * from users";
$result = $mysqli->query( $query );
$num_results = $result->num_rows;
echo "<div><a href='add.php'>Create New Record</a></div>";
if( $num_results ){
echo "<table border='1'>";//start table
//creating our table heading
echo "<tr>";
echo "<th><a href=\"single.php?id={$id}\">Firstname</></th>";
echo "<th>Lastname</th>";
echo "<th>Username</th>";
echo "<th>Action</th>";
echo "</tr>";
//loop to show each records
while( $row = $result->fetch_assoc() ){
//extract row
//this will make $row['firstname'] to
//just $firstname only
extract($row);
//creating new table row per record
echo "<tr>";
echo "<td>{$firstname}</td>";
echo "<td>{$lastname}</td>";
echo "<td>{$username}</td>";
echo "<td>";
echo "<a href='edit.php?id={$id}'>Edit</a>";
echo " / ";
echo "<a href='#' onclick='delete_user( {$id} );'>Delete</a>";
echo "</td>";
echo "</tr>";
}
echo "</table>";//end table
}else{
//if table is empty
echo "No records found.";
}
//disconnect from database
$result->free();
$mysqli->close();
?>
<script type='text/javascript'>
function delete_user( id ){
//this script helps us to
var answer = confirm('Are you sure?');
if ( answer ){ //if user clicked ok
//redirect to url with action as delete and id to the record to be deleted
window.location = 'index.php?action=delete&id=' + id;
}
}
</script>
</body>
</html>
MySQLi教程
在single.php中
$id=$_GET['id'];
$query="select * from users where id='".$id."'";
谢谢你提出的有趣问题。
首先，让我告诉您，尽管您使用的是外观现代的数据库访问库，您使用它的方式与猛犸象化石一样古老。
需要考虑的几件事
- 永远不要按原样使用mysqli，只能以某种更高级抽象库的形式使用
- 不要在应用程序代码中使用real\u escape\u字符串，而只使用准备好的语句
- 切勿将数据库代码与HTML输出混合使用。首先获取数据，然后开始输出
- 切勿使用GET方法修改数据
下面是基于上述原则的示例。它执行所有基本积垢操作：
<?
include 'safemysql.class.php'; // a library
$db = new SafeMysql();
$table = "test";
if($_SERVER['REQUEST_METHOD']=='POST') {
if (isset($_POST['delete'])) {
$db->query("DELETE FROM ?n WHERE id=?i",$table,$_POST['delete']);
} elseif ($_POST['id']) {
$db->query("UPDATE ?n SET name=?s WHERE id=?i",$table,$_POST['name'],$_POST['id']);
} else {
$db->query("INSERT INTO ?n SET name=?s",$table,$_POST['name']);
}
header("Location: http://".$_SERVER['HTTP_HOST'].$_SERVER['PHP_SELF']);
exit;
}
if (!isset($_GET['id'])) {
$LIST = $db->getAll("SELECT * FROM ?n",$table);
include 'list.php';
} else {
if ($_GET['id']) {
$row = $db->getRow("SELECT * FROM ?n WHERE id=?i", $table, $_GET['id']);
foreach ($row as $k => $v) $row[$k]=htmlspecialchars($v);
} else {
$row['name']='';
$row['id']=0;
}
include 'form.php';
}
如果您不想显示表单，请创建另一个名为single.php
的模板，并使用您想要的任何标记single.php
我使用PDO如果你想你也可以用MySQLi
<?php
include("db_connect.php"); // database configuration file
if(isset($_GET['id'])
{
$id = (int) $_GET['id'];
$sql = "SELECT * FROM `users` WHERE id=?";
$query = $conn->prepare($sql); // $conn is PDO object yours can be different
$query->bindValue(1,$id);
$query->execute();
if($query){
$row = $query->fetch(); //
}else{
echo "Error with Database";
}
}
else // Error for the Id selection
{
echo("ID is not selected");
}
?>
您可以使用与显示多条记录相同的代码，但将查询替换为类似“select*from users where id=”。$\u GET['id']。"';我需要替换什么？非常抱歉，我是一个新手/noob，是否需要添加任何代码？首先用于sql注入并使用$\u请求also@YourCommonSense那么我应该使用什么呢？就是您希望从中获取数据的数组$_GET表示查询字符串数据，$\u POST表示POST数据，$\u COOKIE表示cookies+1。也不要使用短标记，如
<a href="?id=0">Add item</a>
<? foreach ($LIST as $row): ?>
<li><a href="?id=<?=$row['id']?>"><?=$row['name']?></a>
<? endforeach ?>
<form method="POST">
<input type="text" name="name" value="<?=$row['name']?>"><br>
<input type="hidden" name="id" value="<?=$row['id']?>">
<input type="submit"><br>
<a href="?">Return to the list</a>
</form>
<? if ($row['id']):?>
<div align=right>
<form method="POST">
<input type="hidden" name="delete" value="<?=$row['id']?>">
<input type="submit" value="Удалить"><br>
</form>
</div>
<?endif?>
if ($_GET['id']) {
$row = $db->getRow("SELECT * FROM ?n WHERE id=?i", $table, $_GET['id']);
foreach ($row as $k => $v) $row[$k]=htmlspecialchars($v);
} else {
$row['name']='';
$row['id']=0;
}
include 'form.php';
<?php
include("db_connect.php"); // database configuration file
if(isset($_GET['id'])
{
$id = (int) $_GET['id'];
$sql = "SELECT * FROM `users` WHERE id=?";
$query = $conn->prepare($sql); // $conn is PDO object yours can be different
$query->bindValue(1,$id);
$query->execute();
if($query){
$row = $query->fetch(); //
}else{
echo "Error with Database";
}
}
else // Error for the Id selection
{
echo("ID is not selected");
}
?>
<table border="1">
<tr>
<td>ID</td>
<td>Firstname</td>
<td>Lastname</td>
</tr>
<tr>
<td><?php echo $row['id]; ?></td>
<td><?php echo $row['firstname']; ?></td>
<td><?php echo $row['lastname']; ?></td>
</tr>
</table>