如何将图像上载到登录用户并获取用户图像PHP MYSQL
我想上传并获取登录的用户的数据，就像Facebook和Twitter一样。这里我的代码所做的是，它检索不同用户登录后发布的所有图像<请帮帮我。我想要的是，如果用户登录，profile page应该只获取登录用户的数据，而不是所有用户的数据，以及如何在mysql中插入用户的图像值。 这是我的SQL选项卡用户和帖子如何将图像上载到登录用户并获取用户图像PHP MYSQL,php,mysql,Php,Mysql,我想上传并获取登录的用户的数据，就像Facebook和Twitter一样。这里我的代码所做的是，它检索不同用户登录后发布的所有图像=$（文档）.height（）-$（窗口）.height（））{ $.ajax({ 键入：“获取”， url:“get_data.php”， 数据：{ “偏移”：标志， “限制”：10 }, 成功：功能（数据）{ $（'#post1'）。追加（数据）； flag+=10； } }); } }); }); 这里是databasedb.php <?php
CREATE TABLE `user` (
`id` int(11) NOT NULL,
`first_name` varchar(50) NOT NULL,
`username` varchar(50) NOT NULL,
`email` varchar(100) NOT NULL,
`password` varchar(100) NOT NULL,
`hash` varchar(32) NOT NULL,
`active` tinyint(1) NOT NULL DEFAULT '0',
`image` varchar(200) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1 ROW_FORMAT=COMPACT;
CREATE TABLE `posts` (
`id` int(11) NOT NULL,
`userid` int(11) NOT NULL,
`image` varchar(255) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1 ROW_FORMAT=COMPACT;
<?php
session_start();
include 'ssql.php';
require 'db.php';
// Check if user is logged in using the session variable
if ( $_SESSION['logged_in'] != 1 ) {
$_SESSION['message'] = "You must log in before viewing your profile page!";
header("location: error.php");
}
else {
// Makes it easier to read
$first_name = $_SESSION['first_name'];
$username = $_SESSION['username'];
$email = $_SESSION['email'];
$active = $_SESSION['active'];
}
?>
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" width="device-width">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<link rel="stylesheet" type="text/css" href="fcb.css" />
<link rel="stylesheet" type="text/css" href="css/font-awesome.css" />
<script type="text/javascript" src="http://code.jquery.com/jquery-latest.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
var flag = 0;
$.ajax({
type: "GET",
url: "get_data.php",
data: {
'offset':0,
'limit' :10
},
success: function(data){
$('#post1').html(data);
flag += 10
}
});
$(window).scroll(function() {
if($(window).scrollTop() >= $(document).height() - $(window).height()) {
$.ajax({
type: "GET",
url: "get_data.php",
data: {
'offset': flag,
'limit' : 10
},
success: function (data) {
$('#post1').append(data);
flag += 10;
}
});
}
});
});
</script>
<body>
<div id="post1">
</div>
</body>
<?php
/* Database connection settings */
$host = 'localhost';
$user = 'root';
$pass = '';
$db = 'accounts';
$mysqli = new mysqli($host,$user,$pass,$db) or die($mysqli->error);
<?php
if (isset($_POST['update'])){
header('Location:profile.php');
$target = "images/".basename($_FILES['image']['name']);
$db = mysqli_connect("localhost", "root", "", "accounts");
$image = $_FILES['image']['name'];
$data = mysqli_query($db, "SELECT `id` FROM `user`");
$sql = "insert into posts (userid, image) values ('$userid', '$image')";
mysqli_query($db, $sql);
if (move_uploaded_file($_FILES['image']['tmp_name'], $target)) {
} else {
}
}
?>
$（文档）.ready（函数（）{
var标志=0；
$.ajax({
键入：“获取”，
url:“get_data.php”，
数据：{
“偏移量”：0，
“限制”：10
},
成功：功能（数据）{
$（'#post1'）.html（数据）；
旗帜+=10
}
});
$（窗口）。滚动（函数（）{
如果（$（窗口）.scrollTop（）>=$（文档）.height（）-$（窗口）.height（））{
$.ajax({
键入：“获取”，
url:“get_data.php”，
数据：{
“偏移”：标志，
“限制”：10
},
成功：功能（数据）{
$（'#post1'）。追加（数据）；
flag+=10；
}
});
}
});
});
<?php
session_start();
include 'ssql.php';
require 'db.php';
// Check if user is logged in using the session variable
if ( $_SESSION['logged_in'] != 1 ) {
$_SESSION['message'] = "You must log in before viewing your profile page!";
header("location: error.php");
}
else {
// Makes it easier to read
$first_name = $_SESSION['first_name'];
$username = $_SESSION['username'];
$email = $_SESSION['email'];
$active = $_SESSION['active'];
}
?>
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" width="device-width">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<link rel="stylesheet" type="text/css" href="fcb.css" />
<link rel="stylesheet" type="text/css" href="css/font-awesome.css" />
<script type="text/javascript" src="http://code.jquery.com/jquery-latest.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
var flag = 0;
$.ajax({
type: "GET",
url: "get_data.php",
data: {
'offset':0,
'limit' :10
},
success: function(data){
$('#post1').html(data);
flag += 10
}
});
$(window).scroll(function() {
if($(window).scrollTop() >= $(document).height() - $(window).height()) {
$.ajax({
type: "GET",
url: "get_data.php",
data: {
'offset': flag,
'limit' : 10
},
success: function (data) {
$('#post1').append(data);
flag += 10;
}
});
}
});
});
</script>
<body>
<div id="post1">
</div>
</body>
<?php
/* Database connection settings */
$host = 'localhost';
$user = 'root';
$pass = '';
$db = 'accounts';
$mysqli = new mysqli($host,$user,$pass,$db) or die($mysqli->error);
<?php
if (isset($_POST['update'])){
header('Location:profile.php');
$target = "images/".basename($_FILES['image']['name']);
$db = mysqli_connect("localhost", "root", "", "accounts");
$image = $_FILES['image']['name'];
$data = mysqli_query($db, "SELECT `id` FROM `user`");
$sql = "insert into posts (userid, image) values ('$userid', '$image')";
mysqli_query($db, $sql);
if (move_uploaded_file($_FILES['image']['tmp_name'], $target)) {
} else {
}
}
?>
您需要在查询中添加用户id的条件，如下所示：
$data = mysqli_query($db, "SELECT `image` FROM `posts` WHERE userid={$loggedInUserId} ORDER BY `id` DESC LIMIT {$limit} OFFSET {$offset} ");
如何在mysqlif（isset（$_POST['update']）{$target=“images/”.basename（$_FILES['image']['name']）；if（move_uploaded_file（$_FILES['image']['tmp_name']，$target））{$db=mysqli_connect（“localhost”，“root”，“accounts”）；$image=$_FILES['image']['name']；$userid=$_sessionuser['id']；//使用您设置的用户id$sql=“insert-into-posts（userid，image）值（“$userid”，“$image”）；“mysqli_查询（$db，$sql）；header（'Location:profile.php'）；}
如果我与任何用户一起登录，我会收到相同的用户帖子。请帮助我检查ssql.php并获取上面提到的\u data.php。请按照我上面提到的更改查询。