通过PHP进行可手持json更新
我试图通过php调用更新json文件。 在我的控制台中,参数不是空的,但是当我检索json文件时,该值不在那里 保存功能如下所示:通过PHP进行可手持json更新,php,json,ajax,handsontable,Php,Json,Ajax,Handsontable,我试图通过php调用更新json文件。 在我的控制台中,参数不是空的,但是当我检索json文件时,该值不在那里 保存功能如下所示: Handsontable.Dom.addEvent(save, 'click', function() { var dataarray = JSON.stringify(hot.getData()); ajax ('json/projectupdate.php', 'POST', {"infos:":dataarray}, function (res) {
Handsontable.Dom.addEvent(save, 'click', function() {
var dataarray = JSON.stringify(hot.getData());
ajax ('json/projectupdate.php', 'POST', {"infos:":dataarray}, function (res) {
console.log (dataarray)
});
[["test1","","gep2","",null,null,null,null,null],["","test1","","gep2",null,null,null,null,null],["dag","","test1","","gep2",null,null,null,null],["","dag","","test1",null,"gep2",null,null,null],["","","dag","","test1",null,"gep2",null,null],["","","","dag",null,"test1",null,"gep2",null],[null,null,null,null,"dag",null,"test1",null,null],[null,null,null,null,null,"dag",null,"test1",null],[null,null,null,null,null,null,"dag",null,"test1"],[null,null,null,null,null,null,null,"dag",null],[null,null,null,null,null,null,null,null,null]]
在控制台中,结果如下所示:
Handsontable.Dom.addEvent(save, 'click', function() {
var dataarray = JSON.stringify(hot.getData());
ajax ('json/projectupdate.php', 'POST', {"infos:":dataarray}, function (res) {
console.log (dataarray)
});
[["test1","","gep2","",null,null,null,null,null],["","test1","","gep2",null,null,null,null,null],["dag","","test1","","gep2",null,null,null,null],["","dag","","test1",null,"gep2",null,null,null],["","","dag","","test1",null,"gep2",null,null],["","","","dag",null,"test1",null,"gep2",null],[null,null,null,null,"dag",null,"test1",null,null],[null,null,null,null,null,"dag",null,"test1",null],[null,null,null,null,null,null,"dag",null,"test1"],[null,null,null,null,null,null,null,"dag",null],[null,null,null,null,null,null,null,null,null]]
这就是我在表格里写的。
然后我将我的var传递(或至少我尝试传递)到我的(projectupdate.php
)php文件:
<?php
$myFile = "project.json";
$fh = fopen($myFile, 'w') or die("can't open file");
$stringData = $_POST['infos'];
$stringData1='{ "data":'$stringData'}';
fwrite($fh, $stringData1);
fclose($fh);
?>
$stringData1='{“数据”:“$stringData'}”
看起来应该是$stringData1='{“数据”:“$stringData'}”
。。。我试过了,但结果是一样的……试着在服务器var_dump($\u POST['infos')上回显它代码>;