正确的JSON格式与PHP
在PHP中生成正确的JSON输出可能有一个简单的问题。我使用以下代码从mysql数据库收集相关数据正确的JSON格式与PHP,php,mysql,json,mysqli,Php,Mysql,Json,Mysqli,在PHP中生成正确的JSON输出可能有一个简单的问题。我使用以下代码从mysql数据库收集相关数据 <?php header('Content-Type: application/json'); $mysqli = new mysqli("localhost", "root", "", "civitas"); if (!$mysqli->set_charset("utf8")) { printf("Error loading character set utf8: %
<?php
header('Content-Type: application/json');
$mysqli = new mysqli("localhost", "root", "", "civitas");
if (!$mysqli->set_charset("utf8")) {
printf("Error loading character set utf8: %s\n", $mysqli->error);
exit();
}
$events = array();
if ($result = $mysqli->query("SELECT title_hu FROM `events`")) {
while ($row = $result->fetch_assoc()) {
$events[] = $row;
}
echo json_encode($events, JSON_PRETTY_PRINT);
}
$result->close();
$mysqli->close();
但对于我使用的工具,格式应为:
{
"events":[{
"title_hu":"Teszt hír",
"content":" lorembalblalba ",
"created_at":"2015-08-31 18:29:58"
},
{
"title_hu":"Teszt hír2",
"content":" lorembalblalba ",
"created_at":"2015-08-31 18:29:58"
},
{
"title_hu":"Teszt hír3",
"content":" lorembalblalba ",
"created_at":"2015-08-31 18:29:58"
}
]
}
我试图将结果放入另一个数组,但在这种情况下,JSON输出只返回数据集的第一项
我做错了什么?
首先将查询更改为
<?php
header('Content-Type: application/json');
$mysqli = new mysqli("localhost", "root", "", "civitas");
if (!$mysqli->set_charset("utf8")) {
printf("Error loading character set utf8: %s\n", $mysqli->error);
exit();
}
$events = array('events'=>array());
if ($result = $mysqli->query("SELECT title_hu, content, created_at FROM `events`")) {
while ($row = $result->fetch_assoc()) {
$events['events'][] = $row;
}
echo json_encode($events, JSON_PRETTY_PRINT);
}
$result->close();
$mysqli->close();
SELECT title_hu,content,created_at FROM `events`
和用于创建JSON使用
$rows = array();// define array
$events = array();// define array
while ($row = $result->fetch_assoc()) {
$events[] = $row;// assign table data to array
}
$rows['events'] = $events;// assign your table data and array to an empty array
echo json_encode($rows, JSON_PRETTY_PRINT);// your final JSON
您可以尝试使用$events['events'][]=$row代码>在循环中,不要忘记在循环之前将$events['events']
声明为数组代码>不适合你?
$rows = array();// define array
$events = array();// define array
while ($row = $result->fetch_assoc()) {
$events[] = $row;// assign table data to array
}
$rows['events'] = $events;// assign your table data and array to an empty array
echo json_encode($rows, JSON_PRETTY_PRINT);// your final JSON