嵌套while循环php-mysql

我有以下代码：

<?php 

if( isset($_POST['groups'])){ 

    $groups = $_POST['groups'];  
    $subject = $_POST['subject']; 

$sql="SELECT 
    a.groupcode, a.groupstudents, a.studentid, 
    b.groupcode, b.coursename, b.studentid, b.date, b.class1, b.attend, b.attendno 

FROM    table_1 a, table_2 b

WHERE   b.groupcode = '$groups' AND b.coursename = '$subject' AND 
        (a.studentid = b.studentid AND a.groupcode = b.groupcode)";

$result=mysqli_query($GLOBALS["___mysqli_ston"], $sql); ?>

<table width="100%" border="1" cellspacing="0" cellpadding="3" > 
<tr> 
    <td align="center"><strong><font size="2">Students</font></strong></td> 
    <td align="center"><strong><font size="2">Date</font></strong></td> 
    <td align="center"><strong><font size="2">Attendance</font></strong>    </td> 
</tr> 

<?php 
while($rows=mysqli_fetch_array($result)){ 

    $date = $rows['date']; $date2 = date("d-F-Y", strtotime($date));

    $class1 = $rows['class1'];
        if ($class1 == 0) $class1 = "No Class"; if ($class1 == 1) $class1 = "Absent";
        if ($class1 == 3) $class1 = "Present"; if ($class1 == 2) $class1 = "Late";
?> 

<tr> 
<td align="center"><font size="2"><?php echo $rows['groupstudents']; ?></font>    </td>
<td align="center"><strong><font size="2"><?php echo $date2; ?></font></strong>    </td> 
<td align="center"><font size="2"><?php echo $class1; ?></font></td>
</tr>

<?php 
    }
?> 

这将给出以下输出。

现在我的问题是如何使用嵌套循环修改代码？！因此，输出为：

谢谢你

---

注：对不起，我没有足够的声誉附上图像。我已经将它们上传到了一个外部站点。

这可能不是最好的解决方案，但我现在想不出更好的解决方案。 在预执行中，我创建了所需的网格，并在布局中显示该网格阵列

<?php 

if( isset($_POST['groups'])){ 

    $groups = $_POST['groups'];  
    $subject = $_POST['subject']; 

$sql="SELECT 
    a.groupcode, a.groupstudents, a.studentid, 
    b.groupcode, b.coursename, b.studentid, b.date, b.class1, b.attend, b.attendno 

FROM    table_1 a, table_2 b

WHERE   b.groupcode = '$groups' AND b.coursename = '$subject' AND 
        (a.studentid = b.studentid AND a.groupcode = b.groupcode)";

$result=mysqli_query($GLOBALS["___mysqli_ston"], $sql); 

$dates = array();
$display = array();

while ($rows=mysqli_fetch_array($result)) {
    if (!isset($display[$rows['groupstudents']])) {
        $display[$rows['groupstudents']] = array();
    }

    if (!isset($dates[strtotime($rows['date'])])) {
        $dates[strtotime($rows['date'])] = count($dates);
    }

    $class1 = $rows['class1'];
    if ($class1 == 0) $class1 = "No Class"; if ($class1 == 1) $class1 = "Absent";
    if ($class1 == 3) $class1 = "Present"; if ($class1 == 2) $class1 = "Late";

    $display[$rows['groupstudents']][$dates[strtotime($rows['date'])]] = $class1;
}

echo '<table width="100%" border="1" cellspacing="0" cellpadding="3">';
echo '<tr>';
echo '<td align="center"><strong><font size="2">Students</font></strong></td>';
foreach ($dates as $date => $reversedIndex) {
    echo '<td align="center"><strong><font size="2">' . date("d-F-Y", $date) . '</font></strong></td>';
}
echo '</tr>';

foreach ($display as $student => $row) {
    echo '<tr>';
    echo '<td align="center"><font size="2">' .  $student . '</font></td>';

    foreach ($dates as $date => $index) {
        echo '<td align="center"><font size="2">';
        if (isset($row[$index])) {
            echo $row[$index];
        } else {
            echo '';
        }
        echo '</font></td>';
    }
    echo '</tr>';
}

echo '</table>';
?>

---

谢谢@Blaatpraat。我会试试这个：它只显示学生的名字。其他列只是空白！非常感谢。非常感谢。非常感谢。工作起来很有魅力：请，您使用的是mysqli，这很好，但请使用事先准备好的语句！顺便说一句，在loopsI WILL I WILL I WILL I WILL:+1谢谢，准备好的语句是最好的。