Php Mysql echo，引用语法帮助（echo，if/else）

我的数据库中有两个表： 1.）成员（id、用户名、电子邮件、密码、salt、tier）=原则（如果Bob的层号大于等于seclevel，则echo contents，否则echo访问被拒绝），但老实说，在语法方面修改我在这里要做的事情有点过头了

有人能帮忙吗？下面是get_opwire.php：

<?php 

include_once 'functions.php';
include_once 'db_connect.php';
sec_session_start();

if(login_check($mysqli) == true) {

$con=mysqli_connect("localhost","mylogin","mypassword","mysqldatabase");
// Check connection
if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }


function getColor($strOption)
{
   switch ($strOption)
   {
       case "Enemy Location":
       return "#cbae80";

       case "Item Location":
       return "#e59350";

       case "Another Category etc":
       return "#b7aaa4";

    }
}


$result = mysqli_query($con,"SELECT opwire.*,members.username FROM opwire 
          LEFT JOIN members on opwire.userid=members.id order by date DESC");

echo "<table border='1'>
<tr>
<th>Category</th>
<th>Contents</th>
<th>Date/Time</th>
<th>Operative</th>
</tr>";

while($row = mysqli_fetch_array($result))
  {
  echo "<tr>";
  echo "<td><font size=1 color='".getColor($row['category'])."'> " . $row['category'] . "</font></td>";
  echo "<td><font size=1 color=#e4d6b5>" . $row['contents'] . "</font></td>";
  echo "<td><font size=1 color=silver>" . $row['date'] . "</font></td>";
  echo "<td><font size=1 color=gold>" . $row['username'] . "</font></td>";
  echo "</tr>";
  }
echo "</table>";

mysqli_close($con);

} else {
   echo 'Access to this area requires security clearance. <br/>';
}

?> 

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垃圾桶里的火箭筒就是一个例子。请不要让它阻止你在这里帮助我。