PHP MYSQL将结果放入一个表中
我有一个返回以下内容的PHP/MySQL查询:PHP MYSQL将结果放入一个表中,php,html,mysql,for-loop,Php,Html,Mysql,For Loop,我有一个返回以下内容的PHP/MySQL查询: array ( 'name' => 'Jess', 'month' => '2020-03-31 12:28:00', 'count' => '1', ) array ( 'name' => 'Bob', 'month' => '2020-04-31 12:28:00', 'count' => '2', ) array ( 'name' => 'Tom', 'month' => '2020-05-31
array ( 'name' => 'Jess', 'month' => '2020-03-31 12:28:00', 'count' => '1', )
array ( 'name' => 'Bob', 'month' => '2020-04-31 12:28:00', 'count' => '2', )
array ( 'name' => 'Tom', 'month' => '2020-05-31 12:28:00', 'count' => '2', )
array ( 'name' => 'Bob', 'month' => '2020-05-31 12:28:00', 'count' => '2', )
月份以有序方式返回(例如,一月记录总是在二月记录之前)。
但是,并非每个用户每个月都会有结果(见上文)
我希望我的数据在html表格中显示如下:
Month Jess Bob Tom
March 1
April 2
May 2 2
以下是我的(非工作)尝试:
只是一个快速更新。通过下面的代码,我成功地得到了我想要的
<?php
/*loop through all customers and print out each induvidual users performance*/
$con = mysqli_connect("localhost","root","","perfmon");
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
exit();
}
//main query for customer names
if ($customers = mysqli_query($con, "SELECT Distinct(customer_name) FROM slog ORDER BY customer_name DESC;")) {
while($row=mysqli_fetch_assoc($customers))
{
//Name of customer
$name = $row["customer_name"];
//Print customer name
print("<b>".$name." </b><br>");
//Used to display total jobs
$total = 0;
$user_list = array("Month");
$monthlist = array();
$st_array = array();
//Loop over the customer names, and pull the modified count per user.
if ($user_perf = mysqli_query($con, "select modified_by as name, created_date as month, count(modified_by) as count from slog where customer_name = '$name' group by modified_by, MONTH(created_date) order by month;")) {
while($row=mysqli_fetch_assoc($user_perf))
{
$month = date("F",strtotime($row["month"]));
$name = $row["name"];
$count = $row["count"];
$total += $row["count"];
//make our left column (months)
if(!in_array($month, $monthlist)){
array_push($monthlist, $month);
}
//Collect all unqiue users, to make our headers array. also stores the order theyre in.
if(!in_array($name, $user_list)){
array_push($user_list, $name);
}
//make a 2d array of all data
$tmp = [$month, $name, $count];
array_push($st_array, $tmp);
}
/**Process fetched data **/
$row = "";
$previous_pos = 1;
$fe = True;
//Print each unique user as a table header
print("<table border='1'>");
print("<tr>");
foreach ($user_list as $th){
print("<th>".$th."</th>");
}
print("</tr>");
//Loop the month array
foreach ($monthlist as $td){
//Loop the user array
foreach ($user_list as $usr){
//Loop our "2d" array (an array containing Month,User,Count)
foreach($st_array as $array_2d){
//If we match the correct month and user, return the count value. This ensures the users return in the correct order.
if ($array_2d[0] == $td && $array_2d[1] == $usr){
//Pos - Get the current position of the selected user.
//Establish how many empty entries need to come before. E.g. User in col 1 has no empty entries infront. User in column2 has 1 entry empty infront (if column 1 is empty).
$pos = array_search($usr, $user_list);
if ($previous_pos != $pos){
$row .= str_repeat("<td>0</td>", ($pos-$previous_pos-1));
}
//Assign our previous position
$previous_pos = $pos;
//If our first entry isn't in column 1, add an extra 0.
if($pos!==1 && $fe)
$row .= "<td>0</td>";
$fe = False;
//Add the data
$row .= "<td>".($array_2d[2])."</td>"; //change to [1] for debug
}
}
}
//Print the table row.
print("<tr><td>".$td ."</td>" . $row ."</tr>");
//Reset our variables.
$row = "";
$fe=True;
$previous_pos = 1;
$first_result = True;
}
print("</table></br>");
mysqli_free_result($user_perf);
}
}
mysqli_free_result($customers);
}
mysqli_close($con);
?>
现在是学习如何使用JOIN
s$tr.=”的时候了$本月。“
将此更改为$tr.=”$本月。"";代码>嗨,Prateik,这似乎并没有解决问题:嗨,Cid,你能扩展JOIN的吗?我完全支持学习,所以如果你能推荐我应该在哪里使用连接,那么我将开始学习。。。感谢在循环中形成数据库查询通常被认为是一种不好的做法。不要先选择用户,然后再为循环中的每个用户选择数据,而应该首先在一个查询中将所需的所有数据连接在一起。
<?php
/*loop through all customers and print out each induvidual users performance*/
$con = mysqli_connect("localhost","root","","perfmon");
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
exit();
}
//main query for customer names
if ($customers = mysqli_query($con, "SELECT Distinct(customer_name) FROM slog ORDER BY customer_name DESC;")) {
while($row=mysqli_fetch_assoc($customers))
{
//Name of customer
$name = $row["customer_name"];
//Print customer name
print("<b>".$name." </b><br>");
//Used to display total jobs
$total = 0;
$user_list = array("Month");
$monthlist = array();
$st_array = array();
//Loop over the customer names, and pull the modified count per user.
if ($user_perf = mysqli_query($con, "select modified_by as name, created_date as month, count(modified_by) as count from slog where customer_name = '$name' group by modified_by, MONTH(created_date) order by month;")) {
while($row=mysqli_fetch_assoc($user_perf))
{
$month = date("F",strtotime($row["month"]));
$name = $row["name"];
$count = $row["count"];
$total += $row["count"];
//make our left column (months)
if(!in_array($month, $monthlist)){
array_push($monthlist, $month);
}
//Collect all unqiue users, to make our headers array. also stores the order theyre in.
if(!in_array($name, $user_list)){
array_push($user_list, $name);
}
//make a 2d array of all data
$tmp = [$month, $name, $count];
array_push($st_array, $tmp);
}
/**Process fetched data **/
$row = "";
$previous_pos = 1;
$fe = True;
//Print each unique user as a table header
print("<table border='1'>");
print("<tr>");
foreach ($user_list as $th){
print("<th>".$th."</th>");
}
print("</tr>");
//Loop the month array
foreach ($monthlist as $td){
//Loop the user array
foreach ($user_list as $usr){
//Loop our "2d" array (an array containing Month,User,Count)
foreach($st_array as $array_2d){
//If we match the correct month and user, return the count value. This ensures the users return in the correct order.
if ($array_2d[0] == $td && $array_2d[1] == $usr){
//Pos - Get the current position of the selected user.
//Establish how many empty entries need to come before. E.g. User in col 1 has no empty entries infront. User in column2 has 1 entry empty infront (if column 1 is empty).
$pos = array_search($usr, $user_list);
if ($previous_pos != $pos){
$row .= str_repeat("<td>0</td>", ($pos-$previous_pos-1));
}
//Assign our previous position
$previous_pos = $pos;
//If our first entry isn't in column 1, add an extra 0.
if($pos!==1 && $fe)
$row .= "<td>0</td>";
$fe = False;
//Add the data
$row .= "<td>".($array_2d[2])."</td>"; //change to [1] for debug
}
}
}
//Print the table row.
print("<tr><td>".$td ."</td>" . $row ."</tr>");
//Reset our variables.
$row = "";
$fe=True;
$previous_pos = 1;
$first_result = True;
}
print("</table></br>");
mysqli_free_result($user_perf);
}
}
mysqli_free_result($customers);
}
mysqli_close($con);
?>