Php MySQLi获取最后一个insert ID并将其传递给true函数
在我的示例中,我试图从查询中检索最后一个_insert(ID)true调用函数这里是我调用函数的地方:Php MySQLi获取最后一个insert ID并将其传递给true函数,php,mysqli,mysql-insert-id,Php,Mysqli,Mysql Insert Id,在我的示例中,我试图从查询中检索最后一个_insert(ID)true调用函数这里是我调用函数的地方: $lead = $_leadh->addLead($lead_data, $call_data['number'], $user); $LeadID = $lead['id']; function addLead(array $lead_data, $number, $user) { //check if lead with same
$lead = $_leadh->addLead($lead_data, $call_data['number'], $user);
$LeadID = $lead['id'];
function addLead(array $lead_data, $number, $user) {
//check if lead with same number and name exist in db
if ($checker = >= 1)
{
//return lead id as existed
$data = $query->fetch_array(MYSQLI_ASSOC);
return array('id'=>$data['lead_id'], 'exists'=>true);
}
else
{
//insert new lead into db
if ($query = $this->QueryDB("INSERT", "INTO leads (lead_name)
VALUES ('".$this->EscapeString($lead_data['lead_name'])))
{
//return lead id as new
return array('id'=>$this->insert_id, 'exists'=>false);
}
else
{
//output error if insertion fail
return false;
}
}}
我没有得到任何结果?这是我的addLead函数:
$lead = $_leadh->addLead($lead_data, $call_data['number'], $user);
$LeadID = $lead['id'];
function addLead(array $lead_data, $number, $user) {
//check if lead with same number and name exist in db
if ($checker = >= 1)
{
//return lead id as existed
$data = $query->fetch_array(MYSQLI_ASSOC);
return array('id'=>$data['lead_id'], 'exists'=>true);
}
else
{
//insert new lead into db
if ($query = $this->QueryDB("INSERT", "INTO leads (lead_name)
VALUES ('".$this->EscapeString($lead_data['lead_name'])))
{
//return lead id as new
return array('id'=>$this->insert_id, 'exists'=>false);
}
else
{
//output error if insertion fail
return false;
}
}}
您正在从
addLead
函数返回数组,但在调用时没有得到任何变量:
$_leadh->addLead($lead_data, $call_data['number'], $user);
$LeadID = $lead['id'];
应如下所示:
$lead = $_leadh->addLead($lead_data, $call_data['number'], $user);
$LeadID = $lead['id'];
是的,很抱歉我错过了代码的这一部分;-)提供
$lead的输出