Php 解决计数查询问题

我有以下代码，我需要从personabisna表中选择所有项目，并从两个表共享personalbisnaId的另一个表中计算具有相同personalbisnaId的项目

 $query="select c.BusinessLogo,
                    c.PersonalBisnaId, 
                    c.account_id,
                      AS Ads from personalbisna As c INNER JOIN myads AS b on b.PersonalBisnaId=c.PersonalBisnaId GROUP BY c.PersonalBisnaId LIMIT $itemfrom,$dataperpage";

这些是桌子

个性化比斯纳表

| PersonalBisnaId| account_id| BusinessLogo
---------------------------------------------
|       1         |   23     |  qwertyu.jpg
|       2         |    4     |  asdfghjk.jpg
|       3         |   12     |  34567gfd.jpg
|       4         |   34     |   drtyujhv.jpg

myads表

|   MyAdsId       | PersonalBisnaId| AdType
---------------------------------------------
|       1         |     2           |  logo
|       2         |     2           |  business card
|       3         |     3           |  logo
|       4         |     2           |   caricalture

我用一些已经回答过的问题来解决我的问题，我真的很困惑，无法解决我的问题

上面的查询应该输出以下内容

| PersonalBisnaId| account_id| BusinessLogo      | AdsCount
-------------------------------------------------------
|       1         |   23     |  qwertyu.jpg      |  0
|       2         |    4     |  asdfghjk.jpg     |  3
|       3         |   12     |  34567gfd.jpg     |  1  
|       4         |   34     |   drtyujhv.jpg    |  0

这就是我所拥有的

$query="SELECT  
                c.BusinessLogo,
                c.PersonalBisnaId, 
                c.account_id,
                c.BusinessName,
                c.BusinessCategory,
                c.BusinessSubCategory,
                c.town,
                c.estate,
                c.street,
                c.road,
                c.building,
                c.Address,
                c.city,
                c.PhoneNumber,
                c.AltPhoneNumber,
                c.website,
                c.Email,
                c.BusinessType              
                COUNT(MyAdsId)  AS AdsCount
                FROM   personalbisna AS c 
                LEFT OUTER JOIN myads AS b 
                ON  b.PersonalBisnaId= c.PersonalBisnaId 
                GROUP BY  c.PersonalBisnaId LIMIT $itemfrom,$dataperpage";

---

Count

查询中缺少聚合

另外，如果要从

Personabisna

表中选择所有项目，则需要

左/右外部联接，而不是
内部联接

SELECT          c.personalbisnaid, 
                c.account_id,
                c.BusinessLogo,
                Count(AdType)      AS AdsCount 
FROM            personalbisna AS c 
LEFT OUTER JOIN myads         AS b 
ON              b.personalbisnaid=c.personalbisnaid 
GROUP BY        c.personalbisnaid, 
                c.account_id,
                c.BusinessLogo

谢谢，但我需要从我的广告中数一数table@xtech-您是否可以在问题中添加预期输出？输出应显示。1.personalBisnaId=3个广告，2.personalBisnaId=2个广告，3.personalBisnaId=8Ads@xtech-你能补充一下吗？我已经补充了预期产出。你可以说明你的期望产出是什么。通常包括什么是RDBMS是很好的。