Php 根据密钥名称将大数组拆分为小数组

我有一个数组，下面我需要根据[location]键将其拆分为更小的数组，所以我想要一个.co.uk数组和一个.com数组。[location]键不限于.co.uk或.com

感谢您的帮助

[22] => Array
    (
        [query] => tttt
        [location] => .co.uk
        [x] => 1292889600
        [y] => 1
        [fullurl] => http://www.tttt.com/
    )

[20] => Array
    (
        [query] => tttt
        [location] => .co.uk
        [x] => 1292976000
        [y] => 1
        [fullurl] => http://www.tttt.com/
    )

[21] => Array
    (
        [query] => tttt
        [location] => .com
        [x] => 1292976000
        [y] => 1
        [fullurl] => http://www.tttt.com/
    )

[19] => Array
    (
        [query] => tttt
        [location] => .co.uk
        [x] => 1293062400
        [y] => 1
        [fullurl] => http://www.tttt.com/
    )

[18] => Array
    (
        [query] => tttt
        [location] => .com
        [x] => 1293062400
        [y] => 1
        [fullurl] => http://www.tttt.com/
    )

[17] => Array
    (
        [query] => tttt
        [location] => .co.uk
        [x] => 1293148800
        [y] => 1
        [fullurl] => http://www.tttt.com/
    )

[16] => Array
    (
        [query] => tttt
        [location] => .com
        [x] => 1293148800
        [y] => 1
        [fullurl] => http://www.tttt.com/
    )

[14] => Array
    (
        [query] => tttt
        [location] => .com
        [x] => 1293235200
        [y] => 1
        [fullurl] => http://www.tttt.com/
    )

您可以这样做：

$byLocation = array();
foreach ($arr as $key => $item) {
    if (!isset($byLocation[$item['location']])) {
        $byLocation[$item['location']] = array();
    }
    $byLocation[$item['location']][$key] = $item;
}

例如，$byLocation['.co.uk'][22]是原始数组的第一项。如果您不想保留原始密钥，只需省略它并使用[]。

您可以这样做：

$byLocation = array();
foreach ($arr as $key => $item) {
    if (!isset($byLocation[$item['location']])) {
        $byLocation[$item['location']] = array();
    }
    $byLocation[$item['location']][$key] = $item;
}

---

例如，$byLocation['.co.uk'][22]是原始数组的第一项。如果您不想保留原始密钥，只需省略它并使用[]。

我认为您只需按如下方式迭代数组即可：

检查当前位置是否为“已知数组”\u key\u是否存在于$domains数组中。如果它没有添加它$域[]=数组

将当前数据作为新数组添加到$domains数组中的相关位置键下。数组_push$domains[]，数组'query'=>XXX，'x'=>

---

我认为您只需要按如下方式迭代数组：

检查当前位置是否为“已知数组”\u key\u是否存在于$domains数组中。如果它没有添加它$域[]=数组

将当前数据作为新数组添加到$domains数组中的相关位置键下。数组_push$domains[]，数组'query'=>XXX，'x'=>

---

工作完美。必须更改$byLocation[$item['location'][$key]=$val；至$byLocation[$item['location'][$key]=$item；不过，它工作得很好。必须更改$byLocation[$item['location'][$key]=$val；至$byLocation[$item['location'][$key]=$item；虽然