PHP表单详细信息不存储在mysql中
我正在AngularJS中创建一个表单，使用它我必须在phpMyAdmin（mysql）中存储个人详细信息。但是，当我填写表格后点击提交按钮时，数据库中没有添加详细信息。请任何人帮助我解决此问题 HTML页面代码：PHP表单详细信息不存储在mysql中,php,html,mysql,angularjs,Php,Html,Mysql,Angularjs,我正在AngularJS中创建一个表单，使用它我必须在phpMyAdmin（mysql）中存储个人详细信息。但是，当我填写表格后点击提交按钮时，数据库中没有添加详细信息。请任何人帮助我解决此问题 HTML页面代码： <!DOCTYPE html> <html> <script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.4/angular.min.js"> </script>
<!DOCTYPE html>
<html>
<script
src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.4/angular.min.js">
</script>
<title> Home </title>
<body>
<div ng-app="myapp" ng-controller="myCtrl">
<form>
<br>
<h1 align="left">ID : <input type="text" ng-model="id"></h1>
<h1 align="left">Name : <input type="text" ng-model="name"></h1>
<h1 align="left">Address : <input type="text" ng-model="address"></h1>
<h1 align="left">Phone : <input type="text" ng-model="phone"></h1>
<input type="button" value="Submit" ng-click="insertData()" />
</br>
</form>
<script>
var app = angular.module('myapp',[]);
app.controller('myCtrl', function($scope, $http){
$scope.insertData = function(){
$http.post("insert.php",{
'id':$scope.id,
'name':$scope.name,
'address':$scope.address,
'phone':$scope.phone})
.then(function successCallback(data,status,headers,config) {
console.log(data);
});
}
});
家
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电话：
var-app=angular.module（'myapp'，[]）；
app.controller（'myCtrl'，函数（$scope，$http）{
$scope.insertData=函数（）{
$http.post（“insert.php”{
'id'：$scope.id，
'name'：$scope.name，
“地址”：$scope.address，
'phone'：$scope.phone}）
.then（函数successCallback（数据、状态、标题、配置）{
控制台日志（数据）；
});
}
});
<?php
$servername = "localhost";
$username = "root";
$password = "bulbul";
$dbname = "angularjs";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$json = file_get_contents('php://input');
$php_array = json_decode($json, TRUE);
$id = $php_array['id'];
$name = $php_array['name'];
$address = $php_array['address'];
$phone = $php_array['phone'];
$sql = "INSERT INTO employee(id,name,address,phone) VALUES(?,?,?,?)";
$stmt = $conn->prepare($sql);
$stmt->bind_param("isss", $id, $name, $address, $phone);
if ($stmt->execute()) {
echo "data inserted";
}
?>
使用.then代替.success as.success在最新的angular 1.x版本中被弃用 使用php代码中的die检查任何服务器端问题为什么表单细节没有添加到数据库中？因为您有以下错误： $http.post（…）。成功不是一个函数 使用浏览器控制台 问题是
.success.then（）<!DOCTYPE html>
<html>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.4/angular.min.js">
</script>
<title> Home </title>
<body>
<div ng-app="myapp" ng-controller="myCtrl">
<form>
<br>
<h1 align="left">ID : <input type="text" ng-model="id"></h1>
<h1 align="left">Name : <input type="text" ng-model="name"></h1>
<h1 align="left">Address : <input type="text" ng-model="address"></h1>
<h1 align="left">Phone : <input type="text" ng-model="phone"></h1>
<input type="button" value="Submit" ng-click="insertData()" />
</br>
</form>
<script>
var app = angular.module('myapp',[]);
app.controller('myCtrl', function($scope, $http){
$scope.insertData = function(){
$http.post("insert.php",{
'id':$scope.id,
'name':$scope.name,
'address':$scope.address,
'phone':$scope.phone})
.then(function successCallback(data,status,headers,config) {
console.log(data);
});
}
});
</script>
</div>
</body>
</html>
家
身份证件：
姓名：
地址:
电话：
var-app=angular.module（'myapp'，[]）；
app.controller（'myCtrl'，函数（$scope，$http）{
$scope.insertData=函数（）{
$http.post（“insert.php”{
'id'：$scope.id，
'name'：$scope.name，
“地址”：$scope.address，
'phone'：$scope.phone}）
.then（函数successCallback（数据、状态、标题、配置）{
控制台日志（数据）；
});
}
});
<?php
$servername = "localhost";
$username = "root";
$password = "bulbul";
$dbname = "angularjs";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$json = file_get_contents('php://input');
$php_array = json_decode($json, TRUE);
$id = $php_array['id'];
$name = $php_array['name'];
$address = $php_array['address'];
$phone = $php_array['phone'];
$sql = "INSERT INTO employee(id,name,address,phone) VALUES(?,?,?,?)";
$stmt = $conn->prepare($sql);
$stmt->bind_param("isss", $id, $name, $address, $phone);
if ($stmt->execute()) {
echo "data inserted";
}
?>
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "angularjs";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$data = json_decode(file_get_contents("php://input"));
$id = $data->id;
$name = $data->name;
$address = $data->address;
$phone = $data->phone;
$sql = "INSERT INTO employee(id,name,address,phone) VALUES(?,?,?,?)";
$stmt = $conn->prepare($sql);
$stmt->bind_param("isss", $id, $name, $address, $phone);
if ($stmt->execute()) {
echo "data inserted";
}
?>
mysql\u error（）mysql.*