Php 字符串匹配
我想从SQL“创建”查询中获取列名 查询:Php 字符串匹配,php,regex,preg-match,Php,Regex,Preg Match,我想从SQL“创建”查询中获取列名 查询: CREATE TABLE 'test' ( 'col1' INT( 10 ) NOT NULL , 'col2' VARCHAR( 50 ) NOT NULL , 'col3' DATE NOT NULL ) ENGINE = MYISAM ; Array ( [0] => Array ( [0] => 'col1\' INT( 10 ) [1] => col1\ [2] => INT [3] => 10 ) [1]
CREATE TABLE 'test' (
'col1' INT( 10 ) NOT NULL ,
'col2' VARCHAR( 50 ) NOT NULL ,
'col3' DATE NOT NULL
) ENGINE = MYISAM ;
Array (
[0] => Array ( [0] => 'col1\' INT( 10 ) [1] => col1\ [2] => INT [3] => 10 )
[1] => Array ( [0] => 'col2\' VARCHAR( 50 ) [1] => col2\ [2] => VARCHAR [3] => 50 )
[2] => Array ( [0] => 'col3\' DATE [1] => col3\ [2] => DATE [3] => )
)
代码:
preg_match_all("/'(.+)' (\w+)\(? ?(\d*) ?\)?/", $sql, $_matches, PREG_SET_ORDER);
输出:
CREATE TABLE 'test' (
'col1' INT( 10 ) NOT NULL ,
'col2' VARCHAR( 50 ) NOT NULL ,
'col3' DATE NOT NULL
) ENGINE = MYISAM ;
Array (
[0] => Array ( [0] => 'col1\' INT( 10 ) [1] => col1\ [2] => INT [3] => 10 )
[1] => Array ( [0] => 'col2\' VARCHAR( 50 ) [1] => col2\ [2] => VARCHAR [3] => 50 )
[2] => Array ( [0] => 'col3\' DATE [1] => col3\ [2] => DATE [3] => )
)
但我需要这样简单的结果:
array(
array('INT( 10 )', 'col1'),
array('VARCHAR( 50 )', 'col2'),
array('DATE', 'col3')
);
我们将感谢所有可能的解决方案。感谢您重新使用上一个答案中的现有查询:
$sql = <<<SQL
CREATE TABLE 'test' (
'col1' INT( 10 ) NOT NULL ,
'col2' VARCHAR( 50 ) NOT NULL ,
'col3' DATE NOT NULL
) ENGINE = MYISAM ;
SQL;
preg_match_all("/'(.+)' (\w+(?:\( ?\d* ?\))?)/", $sql, $matches, PREG_SET_ORDER);
$matches = array_map(function($array) {
return array($array[2], $array[1]);
}, $matches);
var_dump($matches);
preg_match_all("/'(.+)' ((\w+)\(? ?(\d*) ?\)?)/", $sql, $_matches, PREG_SET_ORDER);
$matches = array_map(function($v) {return array(trim($v[2]), $v[1]);}, $_matches);
相关答案:看起来像是
addslashes()
或magic\u quotes
(在preg\u match\u all
之前)有问题@hakre:我问了这个问题。我需要一个更好的解决方案。阅读这个问题..我的php非常生锈,但是你不能做一个简单的查询,然后使用mysql\u fetch\u assoc()
函数并使用foreach
循环它并获取列名吗?