Php 如何获得日期差异

可能重复：

我想从这两个日期中得到区别：天、小时、分钟和秒

php中的

2011-08-17 15:23:24

和

2011-08-11 14:00:11

有人能帮我吗？ 提前感谢。

来自中的示例

由Khaldono在此链接上回答

-请检查之前是否没有人问过该问题。检查或

<?php 
    $date1 = new DateTime('2011-04-01'); 
    $date2 = new DateTime("now"); 
    $interval = $date1->diff($date2); 
    $years = $interval->format('%y'); 
    $months = $interval->format('%m'); 
    $days = $interval->format('%d'); 
    if($years!=0){ 
        $ago = $years.' year(s) ago'; 
    }else{ 
        $ago = ($months == 0 ? $days.' day(s) ago' : $months.' month(s) ago'); 
    } 
    echo $ago; 
?> 

$d1=DateTime::createFromFormat('Y-m-d H:i:s','date1');
$d2=DateTime::createFromFormat('Y-m-d H:i:s','date2');

$interval=$d1->diff($d2);
//use $interval->format(); here

$date1 = "2008-11-01 22:45:00"; 

$date2 = "2009-12-04 13:44:01"; 

$diff = abs(strtotime($date2) - strtotime($date1)); 

$years   = floor($diff / (365*60*60*24)); 
$months  = floor(($diff - $years * 365*60*60*24) / (30*60*60*24)); 
$days    = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));

$hours   = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24)/ (60*60)); 

$minuts  = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24 - $hours*60*60)/ 60); 

$seconds = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24 - $hours*60*60 - $minuts*60)); 

printf("%d years, %d months, %d days, %d hours, %d minuts\n, %d seconds\n", $years, $months, $days, $hours, $minuts, $seconds);