Php JSON编码问题

这种编码方式有什么问题

<?php  
include ("../includes/db_con.php");

    $itemResults = mysql_query("SELECT `sold_for` FROM `items` WHERE `item_did_sell`='1'") or die();
    $mIResults = mysql_query("SELECT `mi_price`, `mi_total_sold` FROM `misc_items` WHERE `mi_total_sold`>'1'") or die();
    $donationResults = mysql_query("SELECT `amount` FROM `donations`") or die(mysql_error());

$total = 0;
$itemTotal = 0;
$mITotal = 0;
$donationTotal = 0;

while($row = mysql_fetch_assoc($itemResults)){  
    $itemTotal += $row['sold_for'];
    $total += $itemTotal;
}

while($row = mysql_fetch_assoc($mIResults)){  
    $mITotal += ($row['mi_price'] * $row['mi_total_sold']);
    $total += $mITotal;
}

while($row = mysql_fetch_assoc($donationResults)){  
    $donationTotal += $row['amount'];
    $total += $donationTotal;
}

header("Content-Type: application/json");
$arr = array('items' => $itemTotal,'mitems' => $mITotal,'donations' => $donationTotal,'total' => $total);
$arr =  json_encode($arr);
echo $arr;

include ("../includes/db_discon.php");
?>

脚本输出： {物品：1000件，数量：0件，捐赠：0件，总数：1000件}

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我的json数组中存在parase错误。这个脚本的输出是什么？它输出：{items:1000，mitems:0，捐赠：0，total:1000}这是非常有效的json，在那里输出，看起来很好。要么你的解析器编码错误，要么你的客户端javascript错误。这是完全有效的json。