使用PHP重新格式化JSON数组
我有一个小的PHP脚本,它拉入一个CSV文件并从中创建一个JSON数组 但是,我想更改输出的JSON数组的格式 PHP:使用PHP重新格式化JSON数组,php,jquery,json,csv,Php,Jquery,Json,Csv,我有一个小的PHP脚本,它拉入一个CSV文件并从中创建一个JSON数组 但是,我想更改输出的JSON数组的格式 PHP: <?php $file = fopen('food.csv', 'r'); $allfile = []; $idsColumnsWanted = array_flip([0, 1, 2]); while (false !== $fields = fgetcsv($file)) { $allfile[] = array_intersect_key($fields,
<?php
$file = fopen('food.csv', 'r');
$allfile = [];
$idsColumnsWanted = array_flip([0, 1, 2]);
while (false !== $fields = fgetcsv($file)) {
$allfile[] = array_intersect_key($fields, $idsColumnsWanted);
}
fclose($file);
?>
因此,它基本上合并了前两项并添加了name
&location
我的food.csv
文件是:
McDonalds,Fast Food,London
Marios,Italian,Manchester
下次请自己尝试一下:
$data = [["McDonalds", "Fast Food", "London"], ["Marios", "Italian", "Manchester"]];
$newData = [];
foreach ($data as $info) {
$newData[] = [
'name' => $info[0] . " " . $info[1],
'location' => $info[2]
];
}
var_dump(json_encode($newData));
输出
string '[{"name":"McDonalds Fast Food","location":"London"},{"name":"Marios Italian","location":"Manchester"}]' (length=104)
您需要以所需格式创建一个新数组,并对其进行简单的
json\u编码。打开CSV文件,然后将CSV解析为一个数组。
沿着这条线走
<?php
$file="1_23.csv";
$csv= file_get_contents($file);
$array = array_map("str_getcsv", explode("\n", $csv));
$json = json_encode($array);
print_r($json);
?>
< /代码> 如果您考虑使用jQuery——这里是
var data = [["McDonalds","Fast Food","London"],["Marios","Italian","Manchester"]];
var formated_data = {};
$.each(data, function(key, val) {
formated_data[key] = {name: val[0] + ' ' + val[1], location: val[2]}
});
console.log(formated_data);
只需编辑使用fgetcsv读取的原始数据。你应该知道如何操作数组以及如何连接字符串。稍加调整,这一切都非常有效。非常感谢!:-)
var data = [["McDonalds","Fast Food","London"],["Marios","Italian","Manchester"]];
var formated_data = {};
$.each(data, function(key, val) {
formated_data[key] = {name: val[0] + ' ' + val[1], location: val[2]}
});
console.log(formated_data);