Php symfony实体中的计算/虚拟字段-如何执行?
我有第一个名为“places”的实体,它映射地名、纬度和经度等位置数据。 另一个名为“用户”的实体存储用户数据,如用户名、用户当前纬度、用户当前经度 我想为计算地理点之间距离的“地点”实体添加一个虚拟字段 我正在使用这个函数-Php symfony实体中的计算/虚拟字段-如何执行?,php,symfony,doctrine-orm,entity,Php,Symfony,Doctrine Orm,Entity,我有第一个名为“places”的实体,它映射地名、纬度和经度等位置数据。 另一个名为“用户”的实体存储用户数据,如用户名、用户当前纬度、用户当前经度 我想为计算地理点之间距离的“地点”实体添加一个虚拟字段 我正在使用这个函数- class Places{ /** * @var integer * * @ORM\Column(name="id", type="integer") * @ORM\Id * @ORM\GeneratedValue(strategy="AUTO") */ p
class Places{
/**
* @var integer
*
* @ORM\Column(name="id", type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $id;
/**
* @var string
* @ORM\Column(name="name", type="string", length=255)
* @Assert\NotBlank()
* @Expose
*/
private $name;
/**
* @var string
* @ORM\Column(name="description", type="string", length=255, nullable=true)
* @Expose
*/
private $description;
/**
* @var float
* @ORM\Column(name="lon", type="float", nullable=true)
* @Expose
*/
private $lon;
/**
* @var float
* @ORM\Column(name="lat", type="float", nullable=true)
* @Expose
*/
private $lat;
/**
* @var integer
* @ORM\ManyToOne(targetEntity="Countries")
* @ORM\JoinColumn(name="country", referencedColumnName="id", onDelete="SET NULL")
* @Assert\NotBlank()
* @Expose
*/
private $country;
/**
* @var string
* @VirtualProperty
* @Type("string")
* @SerializedName("distance")
* @return string
*/
public function distance(){
$longitude1 = '34.7722';//$user->getLon();(?)
$latitude1 = '32.0114';//$user->getLat();(?)
$longitude2 = $this->getLon();
$latitude2 = $this->getLat();
$theta = $longitude1 - $longitude2;
$miles = (sin(deg2rad($latitude1)) * sin(deg2rad($latitude2))) + (cos(deg2rad($latitude1)) * cos(deg2rad($latitude2)) * cos(deg2rad($theta)));
$miles = acos($miles);
$miles = rad2deg($miles);
$miles = $miles * 60 * 1.1515;
$kilometers = $miles * 1.609344;
//return round($kilometers);
return $this->user->getLastName();
}
}
但正如您所看到的,lon1/lat1是硬编码的,因为我无法从places实体中获取用户lan/lat
我该怎么做
谢谢。为什么不将place实体传递给函数
public function distance($place){
$longitude1 = $place->getLon();
$latitude1 = $place->getLat();
$longitude2 = $this->getLon();
$latitude2 = $this->getLat();
$theta = $longitude1 - $longitude2;
$miles = (sin(deg2rad($latitude1)) * sin(deg2rad($latitude2))) + (cos(deg2rad($latitude1)) * cos(deg2rad($latitude2)) * cos(deg2rad($theta)));
$miles = acos($miles);
$miles = rad2deg($miles);
$miles = $miles * 60 * 1.1515;
$kilometers = $miles * 1.609344;
return round($kilometers);
}您在位置和用户之间没有任何关系,您不能在位置实体内部这样做。假设该用户是已登录的用户。您的逻辑必须位于服务中并注入令牌存储,才能让用户登录:
namespace Acme\Bundle\AcmeBundle\Manager;
use Symfony\Component\Security\Core\Authentication\Token\Storage\TokenStorageInterface;
use Acme\Bundle\AcmeBundle\Entity\Location;
class LocationFinder{
/*
* @var TokenStorageInterface
*/
private $tokenStorage;
public function __construct(TokenStorageInterface $tokenStorage)
{
$this->tokenStorage = $tokenStorage;
}
public function getDistance(Location $location)
{
$longitude1 =$this->tokenStorage->getToken()->getUser()->getLon();
$latitude1 = $this->tokenStorage->getToken()->getUser()->getLat();
$longitude2 = $this->getLon();
$latitude2 = $this->getLat();
$theta = $longitude1 - $longitude2;
$miles = (sin(deg2rad($latitude1)) * sin(deg2rad($latitude2))) + (cos(deg2rad($latitude1)) * cos(deg2rad($latitude2)) * cos(deg2rad($theta)));
$miles = acos($miles);
$miles = rad2deg($miles);
$miles = $miles * 60 * 1.1515;
$kilometers = $miles * 1.609344;
return round($kilometers);
}
}
然后必须在Resources\config\services.xml中创建服务
<?xml version="1.0" ?>
<container xmlns="http://symfony.com/schema/dic/services"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://symfony.com/schema/dic/services http://symfony.com/schema/dic/services/services-1.0.xsd">
<services>
<service id="acme.manager.location_finder" class="Acme\Bundle\AcmeBundle\Manager\LocationFinder">
<argument type="service" id="security.token_storage" />
</service>
</services>
</container>
您在这里有更多信息:
我明白了!!
设法使用事件侦听器解决此问题
听众:
class SearchIndexer{
public function __construct(TokenStorageInterface $tokenStorage)
{
$this->tokenStorage = $tokenStorage;
}
public function postLoad (LifecycleEventArgs $args){
$entity = $args->getEntity();
if ($entity instanceof Places) {
$user = $this->tokenStorage->getToken()->getUser();
$entity->setUser_longitude($user->getLastGeoLocationLon());
$entity->setUser_latitude($user->getLastGeoLocationLat());
}
}
}
服务:
services:
doctrine.listener:
class: ApplicationBundle\Listener\SearchIndexer
arguments: ["@security.token_storage"]
tags:
- { name: doctrine.event_listener, event: postLoad }
地点实体:
class Places
{
private $user_longitude;
public function setUser_longitude($user_longitude){
$this->user_longitude = $user_longitude;
}
private $user_latitude;
public function setUser_latitude($user_latitude){
$this->user_latitude = $user_latitude;
}
/**
* @var string
* @VirtualProperty
* @Type("string")
* @SerializedName("distance")
* @return string
*/
public function distance(){
$longitude2 = $this->getLon();
$latitude2 = $this->getLat();
$theta = $this->user_longitude - $longitude2;
$miles = (sin(deg2rad($this->user_latitude)) * sin(deg2rad($latitude2))) + (cos(deg2rad($this->user_latitude)) * cos(deg2rad($latitude2)) * cos(deg2rad($theta)));
$miles = acos($miles);
$miles = rad2deg($miles);
$miles = $miles * 60 * 1.1515;
$kilometers = $miles * 1.609344;
return round($kilometers);
}
//rest of the class
}
我的问题不在于place实体-此代码位于places实体内。我想获取places实体中的用户实体数据,所以将用户实体传递给距离方法?!这就是我要问的——我该怎么做?我的距离函数是在空间实体内部,我不叫它——它是一个虚拟属性,所以你不能。要计算距离,你需要有用户和放置实例对象。如何在这两个实体之间建立一个字段作为关系。Symfony真的知道如何使简单的解决方案变得复杂。为什么不是一个受保护的字段$distance和一个getter getDistance()?@crafter不要责怪框架。开发人员负责创建简单、复杂或复杂的解决方案。
class Places
{
private $user_longitude;
public function setUser_longitude($user_longitude){
$this->user_longitude = $user_longitude;
}
private $user_latitude;
public function setUser_latitude($user_latitude){
$this->user_latitude = $user_latitude;
}
/**
* @var string
* @VirtualProperty
* @Type("string")
* @SerializedName("distance")
* @return string
*/
public function distance(){
$longitude2 = $this->getLon();
$latitude2 = $this->getLat();
$theta = $this->user_longitude - $longitude2;
$miles = (sin(deg2rad($this->user_latitude)) * sin(deg2rad($latitude2))) + (cos(deg2rad($this->user_latitude)) * cos(deg2rad($latitude2)) * cos(deg2rad($theta)));
$miles = acos($miles);
$miles = rad2deg($miles);
$miles = $miles * 60 * 1.1515;
$kilometers = $miles * 1.609344;
return round($kilometers);
}
//rest of the class
}