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Php 如何在HTTP响应体中保留LineFeed_Php_Csv_Curl_Guzzle - Fatal编程技术网

Php 如何在HTTP响应体中保留LineFeed

Php 如何在HTTP响应体中保留LineFeed,php,csv,curl,guzzle,Php,Csv,Curl,Guzzle,我正在做和卷曲要求使用口吻 $client = new GuzzleHttp\Client(); try { $response = $client->get($url); } catch (\GuzzleHttp\Exception\RequestException $ex) { // handle error. } 服务器响应的格式如下: "field1","field2","field3"\n "value1","value2","value3"\n "value

我正在做和卷曲要求使用口吻

$client = new GuzzleHttp\Client();

try {
    $response = $client->get($url);
} catch (\GuzzleHttp\Exception\RequestException $ex) {
    // handle error.
}
服务器响应的格式如下:

"field1","field2","field3"\n
"value1","value2","value3"\n
"value4","","value5"\n
使用GuzzleHttp\Client,我收到以下响应正文

"field1","field2","field3""value1","value2","value3""value4","","value5"\n
是否可以将Guzzle客户端设置为不替换响应正文中的换行符

我们不知道你的反应如何。 我们不知道您是如何看待响应的。 在存在这两个细节的情况下,我不得不猜测您可能必须实现某种类型的响应,以便一次只读入一行响应