Php 如何在HTTP响应体中保留LineFeed
我正在做和卷曲要求使用口吻Php 如何在HTTP响应体中保留LineFeed,php,csv,curl,guzzle,Php,Csv,Curl,Guzzle,我正在做和卷曲要求使用口吻 $client = new GuzzleHttp\Client(); try { $response = $client->get($url); } catch (\GuzzleHttp\Exception\RequestException $ex) { // handle error. } 服务器响应的格式如下: "field1","field2","field3"\n "value1","value2","value3"\n "value
$client = new GuzzleHttp\Client();
try {
$response = $client->get($url);
} catch (\GuzzleHttp\Exception\RequestException $ex) {
// handle error.
}
服务器响应的格式如下:
"field1","field2","field3"\n
"value1","value2","value3"\n
"value4","","value5"\n
使用GuzzleHttp\Client,我收到以下响应正文
"field1","field2","field3""value1","value2","value3""value4","","value5"\n
是否可以将Guzzle客户端设置为不替换响应正文中的换行符
我们不知道你的反应如何。
我们不知道您是如何看待响应的。
在存在这两个细节的情况下,我不得不猜测您可能必须实现某种类型的响应,以便一次只读入一行响应