Php 无法在每年增加行数

我想限制用户每年上传50张照片。比如说，用户可以在2015年上传50张照片，然后用户收到错误消息。同样，2016年用户可以上传50张照片，但2015年用户上传的照片不会被删除

这是我的upload.php

<?php
// set timeout period in seconds
$inactive = 100;
// check to see if $_SESSION['timeout'] is set
if(isset($_SESSION['timeout']) ) {
    $session_life = time() - $_SESSION['timeout'];
    if($session_life > $inactive)
        { session_destroy(); header("Location: logout.php"); }
}
$_SESSION['timeout'] = time();
include "lib/connection.php";
if (!isset($_SESSION['user']))
{
    //die ("Access Denied");
    header("location:index.php?msg=Please login with valid credentials");
}
if (isset($_SESSION['user']))
 { 
     include "lib/top.php";
include "lib/left.php";

?>


            <div class="col-md-10">
            <div class="row">
            <div class="col-md-12">
                <ol class="breadcrumb">
                    <li><a href="dashboard.php">Home</a></li>                    

                    <li class="active">Upload Photo</li>
                </ol>
            </div>
        </div>    
        <?php
            if(!empty($_GET['msg'])) {
    $message = $_GET['msg'];
    print "$message";

            }
    ?>
                 <div class="block block-fill-white">
                    <div class="header">
                        <h2>Upload Photo</h2>
                    </div>
                    <FORM METHOD="POST" ACTION="pic-db-upload.php" enctype = "multipart/form-data">
                    <div class="content controls">
                        <div class="form-row">
                            <div class="col-md-3">Title:</div>
                            <div class="col-md-9"><input type="text" class="form-control" id="title" name="title" required placeholder="Enter some Title"/></div>
                        </div>


                        <div class="form-row">
                            <div class="col-md-3">Description:</div>
                            <div class="col-md-9"><textarea class="form-control" id="description" name="description" required></textarea></div>
                        </div> 
                        <?php
$sel="SELECT * FROM  `category`";
$tab=mysql_query($sel);
                        ?>
                        <div class="form-row">
                            <div class="col-md-3">Category:</div>
                            <div class="col-md-9">
                                <select class="form-control" name="category" required>
                                    <option value="0">Select</option>
                                    <?php
                                    while($row=mysql_fetch_array($tab))
{

                                    ?>
                                    <option value="<?php echo $row['id']; ?>"><?php echo $row['cname']; ?></option>
                                    <?php
}
                        ?>
                                </select>
                            </div>
                        </div>


                        <div class="form-row">
                            <div class="col-md-3">Thumbnail Height:</div>
                            <div class="col-md-9"><input type="text" class="form-control" id="theight" name="theight" required placeholder="Enter height"/></div>
                        </div>
                        <div class="form-row">
                            <div class="col-md-3">Thumbnail Width:</div>
                            <div class="col-md-9"><input type="text" class="form-control" id="twidth" name="twidth" required placeholder="Enter width"/></div>
                        </div>
                        <div class="form-row">
                            <div class="col-md-3">File:</div>
                            <div class="col-md-9">
                                <div class="input-group file">                                    
                                    <input type="text" class="form-control"/>
                                    <input type="file" id="picture" name="picture" required/>
                                    <span class="input-group-btn">
                                        <button class="btn btn-primary" type="button">Browse</button>
                                    </span>
                                </div>
                            </div>
                        </div>     
                          <div class="form-row">
                          <div class="col-md-3">   </div>
                          <div class="col-md-9" style="align:midle">
                          <input type="reset" class="btn btn-danger">
                            <input type="submit" class="btn btn-primary" name="submit" value="UPLOAD">
                            </div>
                        </div>                       
                    </div>
                </div>               
                </form>

            </div>



        </div>
        <?php
        include "lib/bottom.php";
 }
        ?>


and this is my insert query

<?php
ini_set('display_errors', 0);
error_reporting(E_ERROR | E_WARNING | E_PARSE); 
ob_start();
include("lib/connection.php");
if (!isset($_SESSION['user']))
{
    //die ("Access Denied");
    header("location:index.php?msg=Login with valid credentials");
}
if (isset($_SESSION['user']))
 { 

//======================= INSERT =================================================

if($_POST[submit]=="UPLOAD")
  {
if($_POST[title]!="" && $_POST[category]!="" && $_POST[description]!="" && $_FILES[picture][name]=="")
  {
    header("location:upload-photo.php?msg=You have not inserted any picture ");
  }
 else
 {

$resource = mysql_query("SELECT COUNT(id) FROM album");
$count = mysql_result($resource,0);

if ($count < 50)
     {
//======================== THUMBNAIL CODE ======================== 
function thumb($a,$b)
{
    $image_path=$a;
    $new_width=$_POST[twidth];
    $new_height=$_POST[theight];
    $thumb_path=$b;
    $ext=strtolower(end(explode('.',$image_path)));
    if($ext=='jpg'||$ext=='jpeg'||$ext=='gif'||$ext=='png')
    $img=@imagecreatefromjpeg($image_path);
    else
    die("only jpg or jpeg or gif or png format supported");
    $width=imagesx($img);
    $height=imagesy($img);
    $tmp_img=imagecreatetruecolor($new_width,$new_height);
    imagecopyresized($tmp_img,$img,0,0,0,0,$new_width,$new_height,$width,$height);
    imagedestroy($img);
    imagejpeg($tmp_img,$thumb_path);
}

//==================================================================

$p=md5(rand(1,1000));
$pict=$p.".jpg";
$target_path1 = "big_pic/big_".$pict;
copy($_FILES[picture][tmp_name],$target_path1);
$target_path2="thumb_pic/thumb_".$pict;
thumb($target_path1,$target_path2);

$ins = "INSERT INTO `album`(`id`,`date`,`title`,`description`,`cid`,`picture`,`thumbnail`,`default`)VALUES('',now(),'$_POST[title]','$_POST[description]','$_POST[category]','$target_path1','$target_path2','$pict')" ;
mysql_query($ins);
header("location:upload-photo.php?msg=Photo successfully uploaded");
     }
     else
     {
header("location:upload-photo.php?msg=Sorry maximum number of photo uploaded. Please contact system administrator");
     }
     }
}

//======================= END INSERT =================================================
}
 ?>

上传照片
上传照片
标题：
说明：
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缩略图高度：
缩略图宽度：
文件：
浏览
这是我的插入查询
将查询更改为仅统计当前年份中的照片：

SELECT COUNT(*) FROM album WHERE YEAR(date) = YEAR(NOW())

那么问题是什么呢？米安坦数据包。检查注册年份，并记录每个用户上传的照片数量。另外，将照片的URL保存在单独的表格中，这样，如果年份发生变化，您可以轻松删除所有照片。谢谢您，这是$date=date（'Y'）$resource=mysql_查询（“从相册中选择COUNT（*），其中
year
='$date'）$count=mysql\u结果（$resource，0）；如果（$count<500），我不明白为什么需要使用PHP变量来获取年份，因为MySQL本身可以做得很好。