Php 使用下拉列表从数据库中删除数据,但收到错误消息
错误消息:删除记录时出错:您的SQL语法有错误;检查与您的MariaDB服务器版本对应的手册,以了解第1行“1”附近要使用的正确语法 删除成功,但如何删除此错误消息 Output.phpPhp 使用下拉列表从数据库中删除数据,但收到错误消息,php,html,mysql,Php,Html,Mysql,错误消息:删除记录时出错:您的SQL语法有错误;检查与您的MariaDB服务器版本对应的手册,以了解第1行“1”附近要使用的正确语法 删除成功,但如何删除此错误消息 Output.php mysqli_query($link, "CREATE TABLE Student ( Student_Name VARCHAR(100), IC_Number VARCHAR(15), Matric_Number VARC
mysqli_query($link, "CREATE TABLE Student (
Student_Name VARCHAR(100),
IC_Number VARCHAR(15),
Matric_Number VARCHAR(10),
PRIMARY KEY (Matric_Number)
)");
$stdname = $_POST["stdname"];
$icno = $_POST["icno"];
$matricno = $_POST["matricno"];
$data = "INSERT INTO Student (Student_Name, IC_Number, Matric_Number)
VALUES ('$stdname', '$icno', '$matricno')";
delete_form.php
<!DOCTYPE HTML>
<html>
<body>
<form action="todelete.php" method="post">
<h2>Delete Student</h2>
<select name = "dropdownlist">
<?php
$link = mysqli_connect("localhost", "root", "") or die(mysqli_connect_error());
mysqli_select_db($link, "myDataBase") or die(mysqli_error($link));
$result = mysqli_query($link, "SELECT Matric_Number FROM Student");
while($row = mysqli_fetch_array($result)){
echo "<option value ='" . $row['Matric_Number'] . "'>" . $row['Matric_Number'] . '</option>';
}
mysqli_close($link);
?>
<input type="submit" value="Delete">
</select>
<form>
<br><br>
<a href= "view_student.php">Click here to list the table</a>
</body>
</html>
删除学生
todelete.php
<!DOCTYPE HTML>
<html>
<body>
<?php
$link = mysqli_connect("localhost", "root", "") or die(mysqli_connect_error());
mysqli_select_db($link, "myDataBase") or die(mysqli_error($link));
if(isset($_POST['dropdownlist'])){
$dropdownlist1 = $_POST['dropdownlist'];
$result = mysqli_query($link, "DELETE FROM Student WHERE Matric_Number = '$dropdownlist1'");
if (mysqli_query($link, $result)){
echo "Record deleted successfully";
} else {
echo "Error deleting record: " . mysqli_error($link);
}
}
mysqli_close($link);
?>
<br><br>
<a href= "view_student.php">Click here to list the table</a>
</body>
</html>
使用$dropdownlist
代替$dropdownlist1
或使用
mysqli_查询($link,“从学生中删除,其中Matric_编号=”””。$dropdownlist1。”);
警告:您的代码已打开,请使用
请检查$dropdownlist1的内容。我猜这不是一个数字,看看这个