Php mysql二维数组查询结果以邮件形式发送

我需要发送一封邮件使用php邮件功能。需要计算从今天到未来7天每天的早餐、午餐、晚上、晚餐和午夜，其中每个字段标记为1

Mysql表和数据

需要计算从今天到未来7天每天的早餐、午餐、晚上、晚餐和午夜，其中每个字段标记为1

要循环的最简单查询：-

从foodPlan中选择CountBreaken，其中早餐=1，日期=2014-09-17

这样，从今天到连续7天按行排列 列-早餐、午餐、晚上、晚餐、午夜-每个列应提供标记为1的计数，不需要计数

结果需要连同以下数据一起邮寄：-

        $link =mysql_connect("172.17.xx.xxx", "username", "password") 
                              or die(mysql_error());
        //To select the database
        mysql_select_db("dbname") or die(mysql_error());

        //To get the current date 
        $date=date("Y-m-d");

        $dates = array();

        $dates[0] = $today;

        for ($i=1; $i<7; $i++) {
          $dates[$i] =  date('Y-m-d', strtotime("+$i day"));
        }
         .....
         .....

        # This will set the Subject for the  Mail
        $subject = "FOODIE plan";


        $recipient = 'xx@yyyy.com';

        # The following details will be updated in the Body part of the mail
        $message = "Foodie";

        ....
        ....
        mail ( $recipient, $subject, $message, $header );

邮件中的数据应如下所示：- SUM与GROUP BY相结合，提供了SQL中所需的函数

因此，您应该能够使用以下内容：

SELECT
    date,
    SUM(BREAKFAST) as breakfast_total,
    SUM(LUNCH) as lunch_total
FROM foodPlan
WHERE date >= $firstday AND date <= $lastday
GROUP BY date

---

希望这对你有帮助

// Table columns are putted in the array.
$columnNames = array('BREAKFAST','LUNCH','EVENING','DINNER','MIDNIGHT');
$today = date("Y-m-d");

$dates = array();

$dates[0] = $today;

for ($i=1; $i<7; $i++) {
  $dates[$i] =  date('Y-m-d', strtotime("+$i day"));
}

$result = array();
foreach ($columnNames as $column) {
    foreach ($dates as $date) {
        $query = "SELECT count(".$column.") as cnt FROM foodplan WHERE " .$column. "= 1 AND date = '".$date."'";
        $res = mysql_query($query);
        $row = mysql_num_rows($res);
        if ($row > 0) {
            $record = mysql_fetch_assoc($record);
            $result[$date][$column] = $record['cnt'];   
        } else {
            // if we don't found any record in the case.
            $result[$date][$column] = 0;    
        }
    }
}

// creating table to send in email body 
$emailMessage = "<table>
                 <tr>
                    <th>Date</th>";
                    foreach ($columnNames as $cKey => $cValue) { 
                            $emailMessage .= "<th>".$cValue."</th>";
                    }
$emailMessage .= "</tr>";
                    foreach ($result as $rDate => $rDataValue) { 
                        $emailMessage .= "<tr><td>".$rDate."</td>";
                            foreach ($columnNames as $col) { 
                                $emailMessage .= "<td>".$rDataValue[$col]."</td>";
                            }   
                        $emailMessage .= "</tr>";
                    } 
$emailMessage .= "</table>";

---

这将必须显示您想要的表。

请告诉我们您已经做了什么？请查看编辑@Alankar您可以显示您正在获取的数组吗？需要以报表格式打印mysql查询的结果。这看起来像是糟糕的设计