Php Mysql，按字段计数排序

我有一张名为purchased_albums的桌子

id  album_id    member_id   date
4      8              7     2013-12-24 08:17:54
5      9              7     2013-12-29 11:03:35
6      8              10    2013-12-24 08:17:54

我正试图通过购买的专辑来分类。也就是说，它应该计算重复次数最多的唱片集id，并根据该id进行排序。我的查询一直返回null

$q="SELECT COUNT(album_id) as tot,album_id,date  FROM purchased_albums ORDER BY tot DESC";

---

您可以使用联接获取每个相册的计数，然后按结果数量排序：

SELECT pa.*
FROM purchased_albums pa
INNER JOIN
(
    SELECT COUNT(*) qty_purchased, album_id
    FROM purchased_albums
    GROUP BY album_id
) c ON pa.album_id = c.album_id
ORDER BY c.qty_purchased DESC

---

请仔细阅读此代码，您可能会发现您的确切要求

  $q="SELECT COUNT(album_id) as tot,album_id,date FROM purchased_albums GROUP BY album_id ORDER BY album_id DESC";

---

像这样的东西能帮你吗

SELECT `album_id`, `date`, COUNT(*) `purchases`
FROM `purchased_albums`
GROUP BY `album_id`
ORDER BY `purchases` DESC

要挑选购买次数超过3次的相册，请使用

SELECT `album_id`, `date`, COUNT(*) `purchases`
FROM `purchased_albums`
GROUP BY `album_id`
HAVING `purchases` > 3
ORDER BY `purchases` DESC

SELECT `album_id`, `date`, COUNT(*) `purchases`
FROM `purchased_albums`
GROUP BY `album_id`
HAVING `purchases` > 3
ORDER BY `purchases` DESC