Php Symfony4自定义路由器URL生成器

我想自定义路由生成器

以下是我的修改

File: vendor/symfony/framework-bundle/Resources/config/routing.xml 文件：vendor/symfony/frameworkbundle/Resources/config/routing.xml

Symfony\Component\Routing\Generator\UrlGenerator
Symfony\Component\Routing\Generator\UrlGenerator

到

App\Routing\UrlGenerator
App\Routing\UrlGenerator

UrlGenerator类

<?php

namespace App\Routing;

class UrlGenerator extends \Symfony\Component\Routing\Generator\UrlGenerator
{

    protected function doGenerate($variables, $defaults, $requirements, $tokens, $parameters, $name, $referenceType, $hostTokens, array $requiredSchemes = [])
    {
        $url = parent::doGenerate($variables, $defaults, $requirements, $tokens, $parameters, $name, $referenceType, $hostTokens, $requiredSchemes);
        var_dump($url);
        die;
    }
}

---

抱歉，我不知道它已弃用。抱歉，我不知道它已弃用。的可能重复
<argument key="generator_class">App\Routing\UrlGenerator</argument>
<argument key="generator_base_class">App\Routing\UrlGenerator</argument>

<?php

namespace App\Routing;

class UrlGenerator extends \Symfony\Component\Routing\Generator\UrlGenerator
{

    protected function doGenerate($variables, $defaults, $requirements, $tokens, $parameters, $name, $referenceType, $hostTokens, array $requiredSchemes = [])
    {
        $url = parent::doGenerate($variables, $defaults, $requirements, $tokens, $parameters, $name, $referenceType, $hostTokens, $requiredSchemes);
        var_dump($url);
        die;
    }
}

<?php

namespace App\Controller;

use Symfony\Bundle\FrameworkBundle\Controller\AbstractController;
use Symfony\Component\Routing\Annotation\Route;

class DefaultController extends AbstractController
{

    /**
     * @Route("/test")
     */
    public function test()
    {
        $ret = $this->generateUrl('_profiler_exception_css', ['token' => 'test']);
        var_dump($ret);
        die;
    }
}