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Php “提交”按钮在我的表单中不起作用_Php_Html_Css_Forms - Fatal编程技术网

Php “提交”按钮在我的表单中不起作用

Php “提交”按钮在我的表单中不起作用,php,html,css,forms,Php,Html,Css,Forms,这是我的表格。当我单击save时,vales不会被发布并重定向到note.php页面 <form method="post" action="note.php" enctype="multipart/form-data"> <div class="form-group"> <div class="col-sm-1 padding"> <label>Title :</label>

这是我的表格。当我单击save时,vales不会被发布并重定向到note.php页面

<form method="post" action="note.php" enctype="multipart/form-data">
    <div class="form-group">
        <div class="col-sm-1 padding">
            <label>Title :</label>
        </div>
        <div class="col-sm-11 padding">
            <input type="text" class="form-control select2-offscreen form-text" name="title" required autocomplete="off" placeholder="Note Heading" tabindex="-1">
        </div>
    </div>

    <div class="toolbar-btns">
        <div class="file-attach">
            <div class="form-group">  
                <input type="file" name="file[]" multiple="multiple">
            </div>
        </div>
        <div class="form-group">
            <button type="submit" class="btn send-btn" name="btn-note-save">Save</button>
            <input type="reset" style="background-color:#417fb9; color:#fff;" class="btn btn-default"  id="submitForm" value="Clear"></input>
        </div>
    </div>
 </form>

标题:
拯救

我认为您的问题在note.php中。请使用下面的代码获取发布的值

<?php
$title=($_POST['title']);
echo $title;

$pic = $_FILES["file"]["name"];
$folder = "../images/users/";
move_uploaded_file($_FILES['file']["tmp_name"], "$folder".$pic);
?>

我认为您的问题在note.php中。请使用下面的代码获取发布的值

<?php
$title=($_POST['title']);
echo $title;

$pic = $_FILES["file"]["name"];
$folder = "../images/users/";
move_uploaded_file($_FILES['file']["tmp_name"], "$folder".$pic);
?>


嘿,你的起始代码在哪里没有
标签。请将代码包括在
注释中。php
@viswanathan我的意思是添加
注释。php
在问题中,你可以包括note中的代码吗在问题中添加
note.php
,您可以添加note.php中的代码吗