PHP mail（）函数$email和$name变量不起作用，但$message和$subject起作用
提前感谢您的阅读 我有一个部分工作的电子邮件功能：当我在电子邮件地址中硬编码时，它确实会发送一封带有正确消息、主题和标题的电子邮件。上面的SQL插入工作正常，因此我知道它正在将所有变量正确地保存到数据库中 但是，它不会通过PHP mail（）函数$email和$name变量不起作用，但$message和$subject起作用,php,email,variables,Php,Email,Variables,提前感谢您的阅读 我有一个部分工作的电子邮件功能：当我在电子邮件地址中硬编码时，它确实会发送一封带有正确消息、主题和标题的电子邮件。上面的SQL插入工作正常，因此我知道它正在将所有变量正确地保存到数据库中 但是，它不会通过$email、$first\u names或$pass variables发送。它们在邮件中显示为空白，$email在邮件（$email等）功能中不起作用。现在，mail（）仅在我硬编码电子邮件时有效 PHP文件中的代码： $email = $_POST['email']; $
$email$first\u names$pass variables$emailmail（）$email = $_POST['email'];
$first_names = str_replace("'","",$_POST['fname']);
$last_names = str_replace("'","",$_POST['lname']);
$password = $_POST['password'];
$user_type = 2;
$status = 1;
$last_login = '0000-00-00 00:00:00';
$sql_insert = "INSERT INTO `cb_sub_users` (`id`, `email`, `password`, `firstName`, `lastName`, `user_type`, `super_user`, `last_login`, `status`) VALUES (NULL, '$email', '$password', '$first_names', '$last_names', '$user_type', '$super_user_id', '$last_login', '1');";
$check_user = mysql_num_rows(mysql_query("SELECT * FROM `cb_sub_users` WHERE email='".$email."'"));
$message = 'Hi, ' + $first_names + '! Your team has invited you to join Our Site. Your username is ' . $email . ' and your password is ' . $password . '. Log in at blank for analytics you will actually use. If you have any questions, get in touch at help@help.com.';
$subject = 'Welcome to Our Site';
$headers = array("From: help@help.com",
"Reply-To: help@help.com",
"X-Mailer: PHP/" . PHP_VERSION );
$headers = implode("\r\n", $headers);
$body = "From: $name\n E-Mail: $email\n Message:\n $message";
mail('myhardcoded@email.com', $subject, $message, $headers);
ini_set("mail.log", "/tmp/mail.log");
ini_set("mail.add_x_header", TRUE);
非常感谢！非常感谢您的帮助 您的代码易受SQL注入攻击，并且正在使用不推荐使用的MySQL函数。以下是一些可以改进代码的方法：
<?php
$email = isset($_POST['email']?$_POST['email']:"";
$first_name = isset($_POST['fname'])?str_replace("'","",$_POST['fname']):"";
$last_name = isset($_POST['lname'])?str_replace("'","",$_POST['lname']):"";
$password = isset($_POST['password'])?$_POST['password']:"";
if(empty($email)){
echo "Email is empty.";
exit();
}
$name = "$first_name $last_name";
$message = "Hi, $first_name! Your team has invited you to join Our Site. Your username is $email and your password is $password. Log in at http://www.help.com/login for social media analytics you will actually use. If you have any questions, get in touch at help@help.com.\r\n";
$subject = 'Welcome to Help';
$headers = array('From: "Help" <help@help.com>',
"Reply-To: help@help.com",
"X-Mailer: PHP/" . PHP_VERSION
);
$headers = implode("\r\n", $headers);
$body = "From: $name\n E-Mail: $email\n Message:\n $message";
if(!ini_set("mail.log", "/tmp/mail.log")){
echo "<p>Mail Log not set.</p>";
}
if(!ini_set("mail.add_x_header", TRUE)){
echo "<p>X-Headers not enabled.</p>";
}
$result = mail($email, $subject, $message, $headers);
if(!$result){
echo "<p>Message Failed to Send.</p>";
)
?>
因为不清楚您是如何使用SQL的，所以我只是略过了一下，因为您在这里询问
mail（）$first\u names$name$check\u user$check\u user$check\u user$body+$message='Hi'，+$first\u names+'…+mysql.*