Php SQL问题与签出时间
我从一台打孔机上得到的数据如下: 表格Php SQL问题与签出时间,php,jquery,mysql,sql,sql-server,Php,Jquery,Mysql,Sql,Sql Server,我从一台打孔机上得到的数据如下: 表格checkinout: userID checktime checktype 100 2017-07-18 06:53:47.000 I 100 2017-07-18 06:54:47.000 I 102 2017-07-18 06:55:47.000
checkinout
:
userID checktime checktype
100 2017-07-18 06:53:47.000 I
100 2017-07-18 06:54:47.000 I
102 2017-07-18 06:55:47.000 I
104 2017-07-18 06:57:47.000 I
100 2017-07-18 16:53:47.000 O
100 2017-07-18 16:53:47.000 O
102 2017-07-18 16:57:47.000 O
104 2017-07-18 16:58:47.000 O
100 2017-07-18 17:53:47.000 O
我想要这样:
userID checkIN time checkouttime tothours
100 2017-07-18 06:53:47.000 2017-07-18 17:53:47.000 8.50
102 2017-07-18 06:55:47.000 2017-07-18 16:57:47.000 9.30
104 2017-07-18 06:57:47.000 2017-07-18 16:58:47.000 8.50
我使用了很多查询,但都不起作用
这是我的疑问:
DECLARE @temp TABLE
(
UserID INT,
Checktime DATETIME,
CheckStatus CHAR(1)
)
insert into @temp (UserID, Checktime, CheckStatus)
(SELECT BADGENUMBER,CHECKTIME,CHECKTYPE
FROM CHECKINOUT join USERINFO on CHECKINOUT.USERID = USERINFO.USERID where BADGENUMBER ='5969')
SELECT UserID,
CAST(I.CheckTime AS DATE) AS [Date],
CONVERT(VARCHAR(10), I.CheckTime, 108) AS CheckIn,
CONVERT(VARCHAR(10), O.CheckTime, 108) AS CheckOut,
CAST(DATEDIFF(MINUTE,I.checkTime,O.CheckTime)/60.0 AS DECIMAL(18,2)) [Hours]
FROM @temp I
OUTER APPLY (
SELECT TOP 1 Checktime,
CheckStatus
FROM @temp t
WHERE t.UserID = I.UserID
AND t.Checktime > I.Checktime
ORDER BY t.Checktime
) O
WHERE I.CheckStatus = 'I'
AND O.CheckStatus = 'O'.........
这还包括:
DECLARE @temp TABLE
(
UserID INT,
Checktime DATETIME,
CheckStatus CHAR(1)
)
insert into @temp (UserID, Checktime, CheckStatus)
(SELECT BADGENUMBER,CHECKTIME,CHECKTYPE
FROM CHECKINOUT join USERINFO on CHECKINOUT.USERID = USERINFO.USERID where BADGENUMBER ='6079' )
SELECT
t.UserID
, [Date] = DATEADD(dd, 0, DATEDIFF(dd, 0, t.CheckIn))
, CheckIn = CONVERT(VARCHAR(10), t.CheckIn, 108)
, CheckOut = CONVERT(VARCHAR(10), t.CheckOut, 108)
, [Hours] = CAST(DATEDIFF(MINUTE, t.CheckIn, t.CheckOut) / 60. AS DECIMAL(10,2))
FROM (
SELECT
t.UserID
, CheckIn = t.Checktime
, CheckOut = r.Checktime
, RowNum = ROW_NUMBER() OVER (PARTITION BY t.UserID, r.Checktime ORDER BY 1/0)
FROM @temp t
OUTER APPLY (
SELECT TOP 1 *
FROM @temp t2
WHERE t2.UserID = t.UserID
AND t2.Checktime > t.Checktime
AND DATEADD(dd, 0, DATEDIFF(dd, 0, t.Checktime)) = DATEADD(dd, 0, DATEDIFF(dd, 0, t2.Checktime))
AND t2.CheckStatus = 'O'
ORDER BY t2.Checktime
) r
WHERE t.CheckStatus = 'I'
) t
WHERE t.RowNum = 1.......
我猜您希望找到最小签入时间(其中checktype=1)和最大签出时间(其中checktype=0)之间的差异
你能解释一下你是如何计算totalhours的吗?签出时间-签入时间在我的qus中我刚刚做了一个样本首先找出你正在使用的RDBMS并且你没有主键,这可能会在适当的时候被证明有问题我得到了这个错误消息1033,级别15,状态1,第21行ORDER BY子句在视图,内联函数,派生表中无效,子查询和常用表表达式,除非还指定了TOP、OFFSET或FOR XML。我正在使用mssql 2012服务器,请在不使用的情况下按排序的情况下进行尝试,或将其放在末尾仍然无法工作的用户ID、最小日期、最大日期、(最大日期-最小日期)差异显示错误
select userID,
min_date,
max_date,
(max_date - min_date) diff
from (
select distinct userID,
(
select min(checktime)
from checkinout t2
where t1.userID = t2.userID
and t2.checktype = 1
) min_date,
(
select max(checktime)
from checkinout t3
where t1.userID = t3.userID
and t3.checktype = 0
) max_date
from checkinout t1
)
order by userID