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有没有办法用PHP在UPDATE语句中获取值?_Php_Sql - Fatal编程技术网

有没有办法用PHP在UPDATE语句中获取值?

有没有办法用PHP在UPDATE语句中获取值?,php,sql,Php,Sql,在PHP中,我将变为空白或只是说“.”作为一个值 这是我的回声: UPDATE tbl_returnlog SET entry_date = '.''.', suppliername = '.''.', lotid = '.''.', stonedescription = '.''.', returninvc = '.''.', supp_invcdate = '.''.', supp_invc = '.''.', ppc = '.''.', ttl_cost = '.''.', de

在PHP中,我将变为空白或只是说“.”作为一个值

这是我的回声:

UPDATE tbl_returnlog SET entry_date = '.''.', suppliername = '.''.', lotid = '.''.', 
 stonedescription = '.''.', returninvc = '.''.', supp_invcdate = '.''.', 
 supp_invc = '.''.', ppc = '.''.', ttl_cost = '.''.',
 destination = '.''.', actual_ship_date = '.''.', courier = '.''.',
 tracking = '.''.' WHERE suppliername = '.''.';
同时分享我的完整状态:

<?php
   error_reporting(E_ERROR | E_PARSE);

   include "config.php";



    $updatereturnstonedetails = $_POST['updatereturnstonedetails'];
   //echo json_encode($updatereturnstonedetails, true);
   $Stone = json_decode($updatereturnstonedetails, true);

$sql = '';

  //foreach ($StoneArr as $Stone)
  //{

    $entry_date=$Stone['entry_date'];
    $suppliername=$Stone['suppliername'];
    $lotid=$Stone['lotid'];
    $stonedescription=$Stone['stonedescription'];
    $returninvc=$Stone['returninvc'];
    $supp_invcdate=$Stone['supp_invcdate'];
    $supp_invc=$Stone['supp_invc'];
    $ppc=$Stone['ppc'];
    $ttl_cost=$Stone['ttl_cost'];
    $destination=$Stone['destination'];
    $actual_ship_date=$Stone['actual_ship_date'];
    $courier=$Stone['courier'];
    $tracking = $Stone['tracking'];

 $sql .= "UPDATE tbl_returnlog SET entry_date = '.'".$entry_date."'.', suppliername = '.'".$suppliername."'.', lotid = '.'".$lotid."'.', 
 stonedescription = '.'".$stonedescription."'.', returninvc = '.'".$returninvc."'.', supp_invcdate = '.'".$supp_invcdate."'.', 
 supp_invc = '.'".$supp_invc."'.', ppc = '.'".$ppc."'.', ttl_cost = '.'".$ttl_cost."'.',
 destination = '.'".$destination."'.', actual_ship_date = '.'".$actual_ship_date."'.', courier = '.'".$courier."'.',
 tracking = '.'".$tracking."'.' WHERE suppliername = '.'".$suppliername."'.';";
  //}



   echo $sql;

而且还需要去除多余的半氯

其中suppliername='$suppliername'

最佳方法

你应该使用PDO

例如:

使用PDO的示例

$query=“更新表\名称集字段1=:?“

$stmt->bind_参数('field1',$value)

$stmt=$conn->prepare($query)

$stmt->execute()

PDO示例:

$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDBPDO";

$conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
// prepare sql and bind parameters
$stmt = $conn->prepare("INSERT INTO MyGuests (firstname, lastname, email)
        VALUES (:firstname, :lastname, :email)");
$stmt->bindParam(':firstname', $firstname);
$stmt->bindParam(':lastname', $lastname);
$stmt->bindParam(':email', $email);
    
$firstname = "John";
$lastname = "Ramki";
$email = "john@ex.com";
$stmt->execute();
echo "New records created successfully";

您应该使用prepared Statement不要在
'
@可执行文件中使用
,请帮助,如果您知道,我是新手。这可能有助于prepared Statement可能重复的Okay。我将给出PDO连接示例不要捕获异常只是为了显示它。请删除并尝试捕获。您还应该指定connec无法设置字符集或禁用模拟语句,因为在极少数情况下,此代码仍可能容易受到SQL注入的攻击。已删除try-catch块
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDBPDO";

$conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
// prepare sql and bind parameters
$stmt = $conn->prepare("INSERT INTO MyGuests (firstname, lastname, email)
        VALUES (:firstname, :lastname, :email)");
$stmt->bindParam(':firstname', $firstname);
$stmt->bindParam(':lastname', $lastname);
$stmt->bindParam(':email', $email);
    
$firstname = "John";
$lastname = "Ramki";
$email = "john@ex.com";
$stmt->execute();
echo "New records created successfully";