Php 将图像文件获取到body参数中
我正在尝试将文件上载到服务器。我在后端代码中使用SlimFramework和PHP,它是RESTful格式的。如果我通过邮递员上传,图像上传效果非常好,但是我无法使用Swift和Alamofire库让它工作 在后端的路由中,我从body参数获得如下文件:Php 将图像文件获取到body参数中,php,swift,alamofire,Php,Swift,Alamofire,我正在尝试将文件上载到服务器。我在后端代码中使用SlimFramework和PHP,它是RESTful格式的。如果我通过邮递员上传,图像上传效果非常好,但是我无法使用Swift和Alamofire库让它工作 在后端的路由中,我从body参数获得如下文件: $image=$request->getUploadedFiles() 要上传,我使用: $image->moveTo(“myPath”) 在Swift中,我有一个路由器,它提供了.post方法和路由URL,我尝试如下: func upload
$image=$request->getUploadedFiles()代码>
要上传,我使用:
$image->moveTo(“myPath”)代码>
在Swift中,我有一个路由器,它提供了.post
方法和路由URL,我尝试如下:
func uploadImage(user_id: Int, image: Data, completion: @escaping (_ error: Error?, _ success: Bool)->Void) {
let parameters = [
"user_id": user_id,
"newFile": image
] as [String : Any]
Alamofire.request(Router.imageUplaod(parameters: parameters))
.validate(statusCode: 200..<300)
.responseJSON { response in
switch response.result{
case .failure(let error):
completion(error, false)
print(error)
case .success(let value):
//Registered sucesfully! let json = JSON(value)
completion(nil, true)
}//Switch case
}//Alamofire
}
func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {
let chosenProfileImage = info[UIImagePickerControllerEditedImage] as! UIImage
let imageData = UIImageJPEGRepresentation(chosenProfileImage, 0.2)
profileImageView.image = chosenProfileImage
dismiss(animated: true) {
API.uploadImage(user_id: User.sharedInstance.user_id, image: imageData!) { (error, success) in
if success{
print("IMAGE UPLOADDED")
}
}
}
}
let chosenProfileImage = info[UIImagePickerControllerEditedImage] as! UIImage
let imageData = UIImageJPEGRepresentation(chosenProfileImage, 0.2)
profileImageView.image = chosenProfileImage
let base64String = imageData?.base64EncodedString(options: .lineLength64Characters)
这是我的后端路线:
$this->post('/image/upload', function($request, $response, $args){
global $database;
$data = $request->getParsedBody();
$user_id = $data['user_id'];
$files = $request->getUploadedFiles();
if (empty($files['newfile'])) {
throw new Exception('Expected a newfile');
}
$newfile = $files['newfile'];
if ($newfile->getError() === UPLOAD_ERR_OK) {
$uploadFileName = "profileImage".$user_id.".jpg";
$newfile->moveTo("/path/to/image/$uploadFileName");
}
$database->query("UPDATE `users` SET `profile_image_url` = :image WHERE user_id = :user_id");
$database->bind(':image', $uploadFileName);
$database->bind(':user_id', $user_id);
$database->execute();
$Jsonarray['status'] = "true";
$Jsonarray['message'] = "Image Uploaded Successfully";
return $response->withStatus(200)->withHeader('Content-Type', 'application/json')->write(json_encode($Jsonarray));
});
奇怪的是,Alamofire输出状态代码500,但服务器没有告诉我任何关于它的信息。问题一定出在快速部分。所以我甚至不知道如何调试它
我该如何解决这个问题?我解决了这个问题。我是这样重建的:
在客户端上将图像转换为Base64字符串
在后端将其解码为图像
上传
因此,在Swift中,我将其转换为:
func uploadImage(user_id: Int, image: Data, completion: @escaping (_ error: Error?, _ success: Bool)->Void) {
let parameters = [
"user_id": user_id,
"newFile": image
] as [String : Any]
Alamofire.request(Router.imageUplaod(parameters: parameters))
.validate(statusCode: 200..<300)
.responseJSON { response in
switch response.result{
case .failure(let error):
completion(error, false)
print(error)
case .success(let value):
//Registered sucesfully! let json = JSON(value)
completion(nil, true)
}//Switch case
}//Alamofire
}
func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {
let chosenProfileImage = info[UIImagePickerControllerEditedImage] as! UIImage
let imageData = UIImageJPEGRepresentation(chosenProfileImage, 0.2)
profileImageView.image = chosenProfileImage
dismiss(animated: true) {
API.uploadImage(user_id: User.sharedInstance.user_id, image: imageData!) { (error, success) in
if success{
print("IMAGE UPLOADDED")
}
}
}
}
let chosenProfileImage = info[UIImagePickerControllerEditedImage] as! UIImage
let imageData = UIImageJPEGRepresentation(chosenProfileImage, 0.2)
profileImageView.image = chosenProfileImage
let base64String = imageData?.base64EncodedString(options: .lineLength64Characters)
后端基本相同,只是使用base64_decode()将其转换回文件代码>并使用文件内容()代码>功能将其移动到服务器。您正在将参数中“newfile”键的值设置为保存文件内容而不是文件实际内容的数据对象。你就是这个意思吗?Router.imageUpload有什么作用?@Scotthompson the Router.imageUpload只返回.post方法和端点url,它处理授权部分。如果图像可能变大,请使用多部分。