Php Ajax结果以文本形式返回，并将其用作CLNDR.js中JSON数组的值，但它不起作用

我对这个问题的合适标题感到困惑，无论如何，让我解释一下我的问题是什么。我目前正在使用一个插件，我正在尝试使用数据库中的数据（生日）在我的日历中显示事件。我的php查询中的结果是预先格式化的

我的PHP是这样的：

<?php
require 'connection.php';
error_reporting(0); 
session_start();

    $currentYear = date("Y");


    $query = mysqli_query($con,"SELECT * FROM table2");
    $count = mysqli_num_rows($query);

    if($count < 1){ }else{

        while($row = mysqli_fetch_array($query)){


             echo ' { date: \'' .$currentYear. '-' .$row['BirthMonth']. '-' .$row['BirthDay']. '\', title: \'' . $row['LastName'] . ' birthday \' }, ' ;

        }   

    }

?>  

我对CLNDR.js的jquery代码如下：

<script type="text/javascript">
 $(document).ready(function(){

  $.ajax({
          type: 'POST',
          url: 'function/serverdays.php',
          dataType: 'text',
          success: function(data) {

              var year = moment().year();  
              var newyear = moment(year + '-01-01').format('YYYY-MM-DD');
              var valentine = moment(year + '-02-14').format('YYYY-MM-DD');
              var allsaints = moment(year + '-11-01').format('YYYY-MM-DD');
              var allsouls = moment(year + '-11-02').format('YYYY-MM-DD');
              var christmas = moment(year + '-12-25').format('YYYY-MM-DD');
              var lastday = moment(year + '-12-31').format('YYYY-MM-DD');

            var events = [
             data, 
             { date: newyear, title: 'NEW YEAR'},
             { date: valentine, title: 'VALENTINE\'S DAY'},
             { date: allsaints, title: 'ALL SAINTS DAY'},
             { date: allsouls, title: 'ALL SOULS DAY'},
             { date: christmas, title: 'CHRISTMAS DAY'},
             { date: lastday, title: 'LAST DAY OF THE YEAR'},
            ];  

           $('#mini-clndr').clndr({
             template: $('#calendar-template').html(),
             events: events,
             constraints: {
              startDate: moment(year + '-01-01'),
              endDate: moment(year + '-12-31')
             },
             clickEvents: {
               click: function(target) {
                 if(target.events.length) {
                   var daysContainer = $('#mini-clndr').find('.days-container');
                   daysContainer.toggleClass('show-events', true);
                   $('#mini-clndr').find('.x-button').click( function() {
                     daysContainer.toggleClass('show-events', false);
                   });
                 }
               }
             },
             adjacentDaysChangeMonth: true,
             forceSixRows: true
           });

          },
          error:function (xhr, ajaxOptions, thrownError){
              alert(thrownError);
          }
    });




 });
</script>

我的html标签

<div id='mini-clndr'></div>



 <script id="calendar-template" type="text/template">
      <div class="controls">
        <div class="clndr-previous-button">&lsaquo;</div><div class="month"><%= month %></div><div class="clndr-next-button">&rsaquo;</div>
      </div>

      <div class="days-container">
        <div class="days">
          <div class="headers">
            <% _.each(daysOfTheWeek, function(day) { %><div class="day-header"><%= day %></div><% }); %>
          </div>
          <% _.each(days, function(day) { %><div class="<%= day.classes %>" id="<%= day.id %>"><%= day.day %></div><% }); %>
        </div>
    <div class="events">
      <div class="headers">
         <div class="x-button">x</div>
         <div class="event-header">EVENTS</div>
      </div>

      <div class="events-list">
       <% _.each(eventsThisMonth, function(event) { %>
          <div class="event">
              <div class="event-item-name"><%= event.date %> : <%= event.title %></div>
            <div class="event-item-location"><%= event.location %></div>
          </div> 
       <% }); %>
    </div>
  </div>
      </div>

</script>

&伊萨库&rsaquo；
x
事件
: 

但是我从控制台得到一个指向插件的错误

未捕获的TypeError:无法读取未定义的属性“format”

---

不过，我对jquery不是很在行，而且我很难找到对“clndr.js”使用ajax的支持，因为关于它的帖子很少。可能的解决方案是什么？

您没有返回有效的JSON。我强烈建议您使用PHP中需要的属性创建一个对象数组，然后使用

json_encode（）

返回它。我同意@rorymcrossan的说法，PHP返回的字符串不是有效的json字符串。感谢您的快速响应，我在ajax中使用的数据类型如何？使用json_encode（）返回结果后，是否还需要将“text”类型更改为“json”？那我现在就去试试。

            var events = [ 
             { date: '2015-5-29', title: 'Williams birthday' }, 
             { date: '2015-5-29', title: 'Marcus birthday' }, 
             { date: '2015-1-19', title: 'Spear birthday' },
             { date: newyear, title: 'NEW YEAR'},
             { date: valentine, title: 'VALENTINE\'S DAY'},
             { date: allsaints, title: 'ALL SAINTS DAY'},
             { date: allsouls, title: 'ALL SOULS DAY'},
             { date: christmas, title: 'CHRISTMAS DAY'},
             { date: lastday, title: 'LAST DAY OF THE YEAR'},
            ];

<div id='mini-clndr'></div>



 <script id="calendar-template" type="text/template">
      <div class="controls">
        <div class="clndr-previous-button">&lsaquo;</div><div class="month"><%= month %></div><div class="clndr-next-button">&rsaquo;</div>
      </div>

      <div class="days-container">
        <div class="days">
          <div class="headers">
            <% _.each(daysOfTheWeek, function(day) { %><div class="day-header"><%= day %></div><% }); %>
          </div>
          <% _.each(days, function(day) { %><div class="<%= day.classes %>" id="<%= day.id %>"><%= day.day %></div><% }); %>
        </div>
    <div class="events">
      <div class="headers">
         <div class="x-button">x</div>
         <div class="event-header">EVENTS</div>
      </div>

      <div class="events-list">
       <% _.each(eventsThisMonth, function(event) { %>
          <div class="event">
              <div class="event-item-name"><%= event.date %> : <%= event.title %></div>
            <div class="event-item-location"><%= event.location %></div>
          </div> 
       <% }); %>
    </div>
  </div>
      </div>

</script>