多维数组中的PHP搜索
我的大脑很痛,请告诉我。我有以下情况:多维数组中的PHP搜索,php,arrays,multidimensional-array,Php,Arrays,Multidimensional Array,我的大脑很痛,请告诉我。我有以下情况: 我有下一个多维数组: $numbers = array ( "one_digit" => array (1,2,3,4,5), "two_digits" => array (20,21,22,23,24,25), "three_digits" => array (301,302,303,304,304), "mixed_digits" => array (9,29,309,1) ); 我需要一种
- 我有下一个多维数组:
$numbers = array ( "one_digit" => array (1,2,3,4,5), "two_digits" => array (20,21,22,23,24,25), "three_digits" => array (301,302,303,304,304), "mixed_digits" => array (9,29,309,1) );
- 我需要一种在$numbers数组中搜索以下内容的方法: --搜索数字20是否在任何$numbers数组中,并在找到它的位置回显 例如,$find1=m_数组_搜索(“20”,$number);echo“我已在“..$find1.”$numbers子数组中找到搜索值”; 结果:“我在$numbers的两位子数组中找到了搜索值” --搜索数字1是否在任何$numbers数组中,并在找到它的位置回显 例如,$find2=m_数组_搜索(“1”,$number);echo“我已在“..$find2.”$numbers子数组中找到搜索值”; 结果:“我在$number的两个\u数字、混合\u数字子数组中找到了搜索值”
谢谢你 检查一下,如果有帮助,请告诉我
<?php
function array_find_deep($array, $search, $keys = array())
{
foreach($array as $key => $value) {
if (is_array($value)) {
$sub = array_find_deep($value, $search, array_merge($keys, array($key)));
if (count($sub)) {
return $sub;
}
} elseif ($value === $search) {
return array_merge($keys, array($key));
}
}
return array();
}
$numbers = array (
"one_digit" => array (1,2,3,4,5),
"two_digits" => array (20,21,22,23,24,25),
"three_digits" => array (301,302,303,304,304),
"mixed_digits" => array (9,29,309,1)
);
var_dump(array_find_deep($numbers, 20));
var_dump(array_find_deep($numbers, 1));
var_dump(array_find_deep($numbers, 301));
var_dump(array_find_deep($numbers, 309));
?>
您可以将结果存储在变量中,如
$result=array\u find\u deep($numbers,20)
并尝试echo$result[0]
这将给出它在哪个数组中找到值的结果。使用in_array
函数的简单解决方案:
$search = 1;
$keys = [];
foreach ($numbers as $k => $v) {
if (is_array($v) && in_array($search, $v)) $keys[] = $k;
}
echo "I've found the searched value in ". implode(', ', $keys) ." subarray". ((count($keys) > 1)? "s":"") ." of \$numbers";
输出:
I've found the searched value in one_digit, mixed_digits subarrays of $numbers
你可以在一个循环中尝试这个-
$numbers = array (
"one_digit" => array (1,2,3,4,5),
"two_digits" => array (20,21,22,23,24,25),
"three_digits" => array (301,302,303,304,304),
"mixed_digits" => array (9,29,309,1)
);
function search_value($array, $value)
{
$result = array();
foreach($array as $key => $sub) {
// check if element present in sub array
if(array_search($value, $sub) !== false) {
// store the key
$result[] = $key;
}
}
return $result;
}
var_dump(search_value($numbers, 1));
var_dump(search_value($numbers, 5));
输出
array(2) {
[0]=>
string(9) "one_digit"
[1]=>
string(12) "mixed_digits"
}
array(1) {
[0]=>
string(9) "one_digit"
}
@BogdanWebb这是页面上的最佳答案(您可以省略
is\u array()
check;我会的)<当您只希望每个子阵列检查的结果为真/假时,code>array\u search()就太过分了。你可能想重新考虑一下。