Php 每个组都可以获取最新的聊天信息
尝试进行多次选择时Php 每个组都可以获取最新的聊天信息,php,doctrine-orm,doctrine,greatest-n-per-group,slim,Php,Doctrine Orm,Doctrine,Greatest N Per Group,Slim,尝试进行多次选择时 $result = $this->qb->select('c.id','c.message','acc.name as chat_from', 'c.chat_to as count') ->addSelect("SELECT * FROM chat ORDER BY date_deliver DESC") ->from($this->table,'c') ->join('c','account','
$result = $this->qb->select('c.id','c.message','acc.name as chat_from', 'c.chat_to as count')
->addSelect("SELECT * FROM chat ORDER BY date_deliver DESC")
->from($this->table,'c')
->join('c','account','acc', 'c.chat_from = acc.id')
->orderBy('date_sent','DESC')
->groupby('chat_from')
->where('chat_to ='.$id)
->execute();
return $result->fetchAll();
我也试过了
$result = $this->qb->select('c.id','c.message','acc.name as chat_from', 'c.chat_to as count')
->from("SELECT * FROM chat ORDER BY date_deliver DESC",'c')
->join('c','account','acc', 'c.chat_from = acc.id')
->orderBy('date_sent','DESC')
->groupby('chat_from')
->where('chat_to ='.$id)
->execute();
return $result->fetchAll();
我想按分组方式显示数据,然后在最后一个条目中显示数据
我用的是DBAL
请帮助我因为您的问题不清楚,所以我假设您需要获得每个组最近的聊天/消息,这方面的等效SQL将是
SELECT c.id, c.message, a.name as chat_from, c.chat_to as count
FROM account a
JOIN chat c ON(c.chat_from = a.id )
LEFT JOIN chat cc ON(c.chat_from = cc.chat_from AND c.date_sent < cc.date_sent)
WHERE cc.date_sent IS NULL AND c.chat_to = @id
ORDER BY c.date_sent DESC
选择c.id、c.message、a.name作为chat\u from、c.chat\u to作为count
来自帐户a
加入聊天室c ON(c.chat\u from=a.id)
左侧加入聊天室抄送打开(c.chat\u from=cc.chat\u from和c.date\u sent
所以,使用dbal,您可以将上述查询编写为
$this->qb->select( 'c.id', 'c.message', 'a.name as chat_from', 'c.chat_to as count' )
->from( 'account', 'a' )
->join( 'a', 'chat', 'c', 'c.chat_from = a.id' )
->leftJoin( 'c', 'chat', 'cc', 'c.chat_from = cc.chat_from AND c.date_sent < cc.date_sent' )
->where( 'cc.date_sent IS NULL' )
->andWhere( 'c.chat_to =' . $id )
->orderBy( 'c.date_sent', 'DESC' )
->execute();
$this->qb->选择('c.id','c.message','a.name as chat\u from','c.chat\u to as count')
->from('account','a')
->加入('a','chat','c','c.chat\u from=a.id')
->leftJoin('c','chat','cc','c.chat\u from=cc.chat\u from和c.date\u sent其中('cc.date\u sent为NULL')
->andWhere('c.chat_to='。$id)
->orderBy('c.date\u sent','DESC')
->执行();
同样,没有查看示例数据和DDL,这不是一个完整的解决方案
上述代码中出现的任何错误