Php 如何将普通sql查询转换为Zend_Db_Select?
您好,我想将我的普通mysql查询转换为zend.db.select 我想使用以下脚本:Php 如何将普通sql查询转换为Zend_Db_Select?,php,mysql,zend-framework,zend-db-select,Php,Mysql,Zend Framework,Zend Db Select,您好,我想将我的普通mysql查询转换为zend.db.select 我想使用以下脚本: $select = $db->select(); // Add a FROM clause $select->from( ...specify table and columns... ) // Add a WHERE clause $select->where( ...specify search criteria... ) // Add an ORDER BY clause $s
$select = $db->select();
// Add a FROM clause
$select->from( ...specify table and columns... )
// Add a WHERE clause
$select->where( ...specify search criteria... )
// Add an ORDER BY clause
$select->order( ...specify sorting criteria... );
$select->limit(20, 10);
用于我下面的查询
SELECT
IF(derived_messages.toid = '$user', derived_messages.fromid,
derived_messages.toid) friend1,c.UserName,
derived_messages.message, derived_messages.fromid, derived_messages.toid,
derived_messages.is_read,derived_messages.type,derived_messages.id as mesid,
derived_messages.date,
(SELECT M.message_id FROM messagesmapped M where M.message_id= derived_messages.id AND M.user_id ='$user' AND M.important = 1) as MesMapid
FROM
(
SELECT *
FROM messages
WHERE messages.deleted_by NOT
IN ( $user )
ORDER BY Date DESC
) derived_messages
INNER JOIN Users c ON c.MemberID = IF(derived_messages.toid = '$user', derived_messages.fromid,
derived_messages.toid)
WHERE (derived_messages.id IN
(SELECT M.message_id FROM messagesmapped M where M.message_id= derived_messages.id AND M.user_id ='$user' AND M.important = 1)
AND
(derived_messages.toid='$user' OR derived_messages.fromid='$user'))
GROUP BY friend1 ASC
ORDER BY derived_messages.date DESC, derived_messages.id DESC LIMIT $limit $offset
我希望有人能在这方面帮助我
谢谢。有可能但不太可能有人会为您编写查询 我建议处理这样一个查询,将每个单独的子查询编写为自己的
Zend\u Db\u Select
对象,然后使用已有对象的子查询构建最终查询
Zend\u Db\u Select
不直接支持IF
函数,因此需要使用将该语句添加到Select中
这是我所说的一个基本例子。让我们构建以下查询:
SELECT IF(msg.toId = 'drew010', msg.fromId, msg.toId), id, name, age, history.ip
FROM users
JOIN history ON users.id = history.userId
WHERE users.id = (
SELECT id FROM users WHERE loginCount > 1000
)
GROUP BY id,
ORDER BY age DESC
首先构建子选择,选择loginCount
>1000的用户
$subquery1 = $db->select()
->from('users', array('id'))
->where('loginCount > ?', 1000);
接下来,使用IF函数构建外部查询:
$cols = array(
new Zend_Db_Expr('IF(' . $db->quoteInto('msg.toId = ?', 'drew010') . '), msg.fromId, msg.toId'),
'id', 'name', 'age'
);
$query = $db->select()
->from('users', $cols)
->join('history', 'users.id = history.userId', array('ip'))
->where('id = ?', $subquery1)
->group('id')
->order('age DESC');
echo $query;
输出:
SELECT
IF(msg.toId = 'drew010', msg.fromId, msg.toId),
`users`.`id`,
`users`.`name`,
`users`.`age`,
`history`.`ip`
FROM `users`
INNER JOIN `history`
ON users.id = history.userId
WHERE id = (
(SELECT `users`.`id`
FROM `users`
WHERE (loginCount > 1000))
)
GROUP BY `id`
ORDER BY `age` DESC
因此,方法是首先将整个查询分解为单个查询,然后构造外部查询。只要有耐心,慢慢来。然后仔细阅读文档,全面了解您可以获得的信息