Php 从关联数组中获取不同的值

我有两个关联数组，如下所示：

$array1 = array("field1"=>1,"field2"=>1,"field3"=>1,"field4"=>1,"field5"=>1);

$array2 = array("field1"=>1,"field2"=>0,"field3"=>1,"field4"=>0,"field5"=>1);

现在我想合并并找到不同的值

我试过：

但它返回以下输出：

Array
(
    [field1] => 1
    [field2] => 1
    [field3] => 1
    [field4] => 1
    [field5] => 1
)

我需要输出为

Array
(
    [field2] => 1
    [field4] => 1
)

如何实现这一点？

试试看

它通过额外的索引检查来计算数组的差异

$array1 = array("field1"=>1,"field2"=>1,"field3"=>1,"field4"=>1,"field5"=>1);

$array2 = array("field1"=>1,"field2"=>0,"field3"=>1,"field4"=>0,"field5"=>1);

$result =  array_diff_assoc($array1,$array2) ;

echo "<pre>";
print_r($result);

$array1=数组（“field1”=>1，“field2”=>1，“field3”=>1，“field4”=>1，“field5”=>1）；
$array2=数组（“字段1”=>1，“字段2”=>0，“字段3”=>1，“字段4”=>0，“字段5”=>1）；
$result=array_diff_assoc（$array1，$array2）；
回声“；
打印（结果）；

现场演示：

试试看

它通过额外的索引检查来计算数组的差异

$array1 = array("field1"=>1,"field2"=>1,"field3"=>1,"field4"=>1,"field5"=>1);

$array2 = array("field1"=>1,"field2"=>0,"field3"=>1,"field4"=>0,"field5"=>1);

$result =  array_diff_assoc($array1,$array2) ;

echo "<pre>";
print_r($result);

$array1=数组（“field1”=>1，“field2”=>1，“field3”=>1，“field4”=>1，“field5”=>1）；
$array2=数组（“字段1”=>1，“字段2”=>0，“字段3”=>1，“字段4”=>0，“字段5”=>1）；
$result=array_diff_assoc（$array1，$array2）；
回声“；
打印（结果）；

---

现场演示：

非常简单。您必须查找数组\u diff\u assoc（）函数

---

希望有帮助

这很简单。您必须查找数组\u diff\u assoc（）函数

希望有帮助

 How it Works :- Returns an array containing all the values from array1 that are 
            not present in any of the other arrays (in your case $array2).
$array1 = array("field1"=>1,"field2"=>1,"field3"=>1,"field4"=>1,"field5"=>1);
$array2 = array("field1"=>1,"field2"=>0,"field3"=>1,"field4"=>0,"field5"=>1);
$output =  array_diff_assoc($array1,$array2) ;
var_dump($output);