php函数将Unix时间戳转换为分钟、小时或天，如digg？

我需要一个php函数将unix时间戳转换为：

15秒

或

45分钟

或

3小时

而不是这样：2秒5分钟9小时

我只想要一个像digg这样的值（变得流行xx xxxxx）

---

谢谢

PHP没有内置函数来为您执行此操作，因此您必须手动执行。此函数将获取以天、小时、分钟或秒为单位的差值，并以“X天/小时/分钟/秒”格式返回：

<?php
function GetTimeDiff($timestamp) {
    $how_log_ago = '';
    $seconds = time() - $timestamp; 
    $minutes = (int)($seconds / 60);
    $hours = (int)($minutes / 60);
    $days = (int)($hours / 24);
    if ($days >= 1) {
      $how_log_ago = $days . ' day' . ($days != 1 ? 's' : '');
    } else if ($hours >= 1) {
      $how_log_ago = $hours . ' hour' . ($hours != 1 ? 's' : '');
    } else if ($minutes >= 1) {
      $how_log_ago = $minutes . ' minute' . ($minutes != 1 ? 's' : '');
    } else {
      $how_log_ago = $seconds . ' second' . ($seconds != 1 ? 's' : '');
    }
    return $how_log_ago;
?>

---

PHP没有内置函数来为您执行此操作，因此您必须手动执行。此函数将获取以天、小时、分钟或秒为单位的差值，并以“X天/小时/分钟/秒”格式返回：

<?php
function GetTimeDiff($timestamp) {
    $how_log_ago = '';
    $seconds = time() - $timestamp; 
    $minutes = (int)($seconds / 60);
    $hours = (int)($minutes / 60);
    $days = (int)($hours / 24);
    if ($days >= 1) {
      $how_log_ago = $days . ' day' . ($days != 1 ? 's' : '');
    } else if ($hours >= 1) {
      $how_log_ago = $hours . ' hour' . ($hours != 1 ? 's' : '');
    } else if ($minutes >= 1) {
      $how_log_ago = $minutes . ' minute' . ($minutes != 1 ? 's' : '');
    } else {
      $how_log_ago = $seconds . ' second' . ($seconds != 1 ? 's' : '');
    }
    return $how_log_ago;
?>

<代码> > P>如果这是一个网站，你可以考虑。否则，算法相当简单。比如：

$diff = $date - $now;
if ($diff > 2 * ONE_YEAR)
    return sprintf("%d years", round($diff / ONE_YEAR));
else if ($diff > ONE_YEAR)
    return "1 year";
else if ($diff > 2 * ONE_MONTH)
    return sprintf("%d months", round($diff / ONE_MONTH));
...etc...

如果这是一个网站，你可以考虑。否则，算法相当简单。比如：

$diff = $date - $now;
if ($diff > 2 * ONE_YEAR)
    return sprintf("%d years", round($diff / ONE_YEAR));
else if ($diff > ONE_YEAR)
    return "1 year";
else if ($diff > 2 * ONE_MONTH)
    return sprintf("%d months", round($diff / ONE_MONTH));
...etc...

试试这个：

function toFriendlyTime($seconds) {
  $measures = array(
    'day'=>24*60*60,
    'hour'=>60*60,
    'minute'=>60,
    'second'=>1,
    );
  foreach ($measures as $label=>$amount) {
    if ($seconds >= $amount) {  
      $howMany = floor($seconds / $amount);
      return $howMany." ".$label.($howMany > 1 ? "s" : "");
    }
  } 
  return "now";
}   

正如您所见，它还可以灵活地添加/删除您认为合适的时间度量。只需确保从最大到最小的顺序。测试：

print(                           
    toFriendlyTime(0)."\n"           
    .toFriendlyTime(1)."\n"          
    .toFriendlyTime(2)."\n"          
    .toFriendlyTime(60)."\n"         
    .toFriendlyTime(3600)."\n"   
    .toFriendlyTime(24*3600)."\n"                                               
    );

结果：

now
1 second
2 seconds
1 minute
1 hour
1 day

试试这个：

function toFriendlyTime($seconds) {
  $measures = array(
    'day'=>24*60*60,
    'hour'=>60*60,
    'minute'=>60,
    'second'=>1,
    );
  foreach ($measures as $label=>$amount) {
    if ($seconds >= $amount) {  
      $howMany = floor($seconds / $amount);
      return $howMany." ".$label.($howMany > 1 ? "s" : "");
    }
  } 
  return "now";
}   

正如您所见，它还可以灵活地添加/删除您认为合适的时间度量。只需确保从最大到最小的顺序。测试：

print(                           
    toFriendlyTime(0)."\n"           
    .toFriendlyTime(1)."\n"          
    .toFriendlyTime(2)."\n"          
    .toFriendlyTime(60)."\n"         
    .toFriendlyTime(3600)."\n"   
    .toFriendlyTime(24*3600)."\n"                                               
    );

结果：

now
1 second
2 seconds
1 minute
1 hour
1 day