Php 如何在如图所示的表格中插入上一页的tusername

我有一个页面，在那里我发送tusername，然后在第二个页面上创建表单。 我想使用该表单在表中添加多个数据。当请求id并由us输入sub_代码时，表将保存如下数据

---

我想这可以帮到你

<?php

include("db.php");

// Lets test if the form has been submitted

 if(isset($_POST['SubmitCheck'])) {
 // The form has been submited
     $tusername =$_REQUEST['tusername'];

foreach($_POST['sub_code'] as $sub_code) {
                        //insert your data

  @mysql_query("update INTO `techsub`(sub_code, tusername) 
 VALUES ('$sub_code','$tusername') where tusername='$tusername'"); 

 }

    }

else {
    // The form has not been posted
    }
?>
<form id="Form1" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">

    Subject One: <input type="text" name="sub_code[1]"><br>
    Subject Two: <input type="text" name="sub_code[2]"><br>
    Subject Three:<input type="text" name="sub_code[3]"><br>
    Subject Four: <input type="text" name="sub_code[4]"><br>

    <input type="hidden" name="SubmitCheck" value="Assign">
    <input type="Submit" name="Form1_Submit" >
</form>

可爱的漏洞。享受你的服务器pwn3d。我不会把它上传到服务器上。这是一个学校项目。不走运，先生，单击提交后第9行“$tusername=$\u请求['tusername']；”中出现错误。因为它想在提交后重新命名。如何使用提交表单发送tusername。@JasjeetSingh您从哪里获得tusername的价值？您是否声明了任何会话变量？
<?php

include("db.php");

// Lets test if the form has been submitted

 if(isset($_POST['SubmitCheck'])) {
 // The form has been submited
     $tusername =$_REQUEST['tusername'];

foreach($_POST['sub_code'] as $sub_code) {
                        //insert your data

  @mysql_query("update INTO `techsub`(sub_code, tusername) 
 VALUES ('$sub_code','$tusername') where tusername='$tusername'"); 

 }

    }

else {
    // The form has not been posted
    }
?>
<form id="Form1" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">

    Subject One: <input type="text" name="sub_code[1]"><br>
    Subject Two: <input type="text" name="sub_code[2]"><br>
    Subject Three:<input type="text" name="sub_code[3]"><br>
    Subject Four: <input type="text" name="sub_code[4]"><br>

    <input type="hidden" name="SubmitCheck" value="Assign">
    <input type="Submit" name="Form1_Submit" >
</form>