Php 关联数组中的左联接

我想做一个图像库。有一些相册里面有图像，在索引页上我想显示一些相册，当你点击它时，你就会转到那个相册。我可以显示相册名称，但我想用随机函数显示这些相册中的图像。我希望你明白我想做什么。 问题是我无法接触到图像

我有两个关联数组，一个用于相册，一个用于图像。专辑中的那个看起来像这样

function get_albums() {
$albums = array();

$albums_query = mysql_query("
SELECT `albums`.`album_id`, `albums`.`timestamp`, `albums`.`name`,     
LEFT(`albums`.`description`, 50) as `description`, COUNT(`images`.`image_id`) as `image_count`
FROM `albums`
LEFT JOIN `images`
ON `albums`.`album_id` = `images`.`album_id`
GROUP BY `albums`.`album_id`
")or die(mysql_error());

while ($albums_row = mysql_fetch_assoc($albums_query)) {
    $albums[] = array(
        'id' => $albums_row['album_id'],
        'timestamp' => $albums_row['timestamp'],
        'name' => $albums_row['name'],
        'description' => $albums_row['description'],
        'count' => $albums_row['image_count']       
        );
}

return $albums;
}

function get_images($album_id) {
$album_id = (int)$album_id;

$images = array();

$image_query = mysql_query("SELECT `image_id`, `image_name`, `album_id`, `timestamp`, `ext` FROM `images` WHERE `album_id`=$album_id");
while ($images_row = mysql_fetch_assoc($image_query)) {
    echo $images_row['image_id'];

    $images[] = array(
    'id' => $images_row['image_id'],
    'img_name' => $images_row['image_name'],
    'album' => $images_row['album_id'],
    'timestamp' => $images_row['timestamp'],
    'ext' => $images_row['ext']
    );
}
return $images;
}

while ($albums_row = mysql_fetch_assoc($albums_query)) {
    $albums[] = array(
        'id' => $albums_row['album_id'],
        'timestamp' => $albums_row['timestamp'],
        'name' => $albums_row['name'],
        'description' => $albums_row['description'],
        'count' => $albums_row['image_count'],
        'img_name' => $albums_row['image_name'],
        'ext' => $albums_row['ext']         
        );   

$albums = get_albums();

if (isset($albums)) {
foreach ($albums as $album) {
    echo '<a href="view_album.php?album_id=', $album["id"], '"><img src="uploads/thumbs/', $album["id"] ,'/', $album['img_name'],'.', $album["ext"],'" />', $album['name'], '</a>';
}
}

对于图像，它看起来是这样的

function get_albums() {
$albums = array();

$albums_query = mysql_query("
SELECT `albums`.`album_id`, `albums`.`timestamp`, `albums`.`name`,     
LEFT(`albums`.`description`, 50) as `description`, COUNT(`images`.`image_id`) as `image_count`
FROM `albums`
LEFT JOIN `images`
ON `albums`.`album_id` = `images`.`album_id`
GROUP BY `albums`.`album_id`
")or die(mysql_error());

while ($albums_row = mysql_fetch_assoc($albums_query)) {
    $albums[] = array(
        'id' => $albums_row['album_id'],
        'timestamp' => $albums_row['timestamp'],
        'name' => $albums_row['name'],
        'description' => $albums_row['description'],
        'count' => $albums_row['image_count']       
        );
}

return $albums;
}

function get_images($album_id) {
$album_id = (int)$album_id;

$images = array();

$image_query = mysql_query("SELECT `image_id`, `image_name`, `album_id`, `timestamp`, `ext` FROM `images` WHERE `album_id`=$album_id");
while ($images_row = mysql_fetch_assoc($image_query)) {
    echo $images_row['image_id'];

    $images[] = array(
    'id' => $images_row['image_id'],
    'img_name' => $images_row['image_name'],
    'album' => $images_row['album_id'],
    'timestamp' => $images_row['timestamp'],
    'ext' => $images_row['ext']
    );
}
return $images;
}

while ($albums_row = mysql_fetch_assoc($albums_query)) {
    $albums[] = array(
        'id' => $albums_row['album_id'],
        'timestamp' => $albums_row['timestamp'],
        'name' => $albums_row['name'],
        'description' => $albums_row['description'],
        'count' => $albums_row['image_count'],
        'img_name' => $albums_row['image_name'],
        'ext' => $albums_row['ext']         
        );   

$albums = get_albums();

if (isset($albums)) {
foreach ($albums as $album) {
    echo '<a href="view_album.php?album_id=', $album["id"], '"><img src="uploads/thumbs/', $album["id"] ,'/', $album['img_name'],'.', $album["ext"],'" />', $album['name'], '</a>';
}
}

我认为在get_albums函数中，通过左连接函数，我可以通过添加图像名称和扩展名来访问图像，如下所示

function get_albums() {
$albums = array();

$albums_query = mysql_query("
SELECT `albums`.`album_id`, `albums`.`timestamp`, `albums`.`name`,     
LEFT(`albums`.`description`, 50) as `description`, COUNT(`images`.`image_id`) as `image_count`
FROM `albums`
LEFT JOIN `images`
ON `albums`.`album_id` = `images`.`album_id`
GROUP BY `albums`.`album_id`
")or die(mysql_error());

while ($albums_row = mysql_fetch_assoc($albums_query)) {
    $albums[] = array(
        'id' => $albums_row['album_id'],
        'timestamp' => $albums_row['timestamp'],
        'name' => $albums_row['name'],
        'description' => $albums_row['description'],
        'count' => $albums_row['image_count']       
        );
}

return $albums;
}

function get_images($album_id) {
$album_id = (int)$album_id;

$images = array();

$image_query = mysql_query("SELECT `image_id`, `image_name`, `album_id`, `timestamp`, `ext` FROM `images` WHERE `album_id`=$album_id");
while ($images_row = mysql_fetch_assoc($image_query)) {
    echo $images_row['image_id'];

    $images[] = array(
    'id' => $images_row['image_id'],
    'img_name' => $images_row['image_name'],
    'album' => $images_row['album_id'],
    'timestamp' => $images_row['timestamp'],
    'ext' => $images_row['ext']
    );
}
return $images;
}

while ($albums_row = mysql_fetch_assoc($albums_query)) {
    $albums[] = array(
        'id' => $albums_row['album_id'],
        'timestamp' => $albums_row['timestamp'],
        'name' => $albums_row['name'],
        'description' => $albums_row['description'],
        'count' => $albums_row['image_count'],
        'img_name' => $albums_row['image_name'],
        'ext' => $albums_row['ext']         
        );   

$albums = get_albums();

if (isset($albums)) {
foreach ($albums as $album) {
    echo '<a href="view_album.php?album_id=', $album["id"], '"><img src="uploads/thumbs/', $album["id"] ,'/', $album['img_name'],'.', $album["ext"],'" />', $album['name'], '</a>';
}
}

然后像这样在索引页中使用它

function get_albums() {
$albums = array();

$albums_query = mysql_query("
SELECT `albums`.`album_id`, `albums`.`timestamp`, `albums`.`name`,     
LEFT(`albums`.`description`, 50) as `description`, COUNT(`images`.`image_id`) as `image_count`
FROM `albums`
LEFT JOIN `images`
ON `albums`.`album_id` = `images`.`album_id`
GROUP BY `albums`.`album_id`
")or die(mysql_error());

while ($albums_row = mysql_fetch_assoc($albums_query)) {
    $albums[] = array(
        'id' => $albums_row['album_id'],
        'timestamp' => $albums_row['timestamp'],
        'name' => $albums_row['name'],
        'description' => $albums_row['description'],
        'count' => $albums_row['image_count']       
        );
}

return $albums;
}

function get_images($album_id) {
$album_id = (int)$album_id;

$images = array();

$image_query = mysql_query("SELECT `image_id`, `image_name`, `album_id`, `timestamp`, `ext` FROM `images` WHERE `album_id`=$album_id");
while ($images_row = mysql_fetch_assoc($image_query)) {
    echo $images_row['image_id'];

    $images[] = array(
    'id' => $images_row['image_id'],
    'img_name' => $images_row['image_name'],
    'album' => $images_row['album_id'],
    'timestamp' => $images_row['timestamp'],
    'ext' => $images_row['ext']
    );
}
return $images;
}

while ($albums_row = mysql_fetch_assoc($albums_query)) {
    $albums[] = array(
        'id' => $albums_row['album_id'],
        'timestamp' => $albums_row['timestamp'],
        'name' => $albums_row['name'],
        'description' => $albums_row['description'],
        'count' => $albums_row['image_count'],
        'img_name' => $albums_row['image_name'],
        'ext' => $albums_row['ext']         
        );   

$albums = get_albums();

if (isset($albums)) {
foreach ($albums as $album) {
    echo '<a href="view_album.php?album_id=', $album["id"], '"><img src="uploads/thumbs/', $album["id"] ,'/', $album['img_name'],'.', $album["ext"],'" />', $album['name'], '</a>';
}
}

$albums=get_albums（）；
如果（isset（$albums））{
foreach（$albums作为$album）{
回声'；
}
}

但结果是这样的；

---

我做错了什么？

为什么不先进行一个大型查询，将所有数据连接起来，然后按自己的意愿显示出来，如下所示：

sql="SELECT * FROM albums a INNER JOIN images i ON a.album_id = i.album_id WHERE a.album_id =" . $album_id;

$result = mysql_query(sql);

while ($row = mysql_fetch_array($result))  {
     echo '<a href="view_album.php?album_id=' . $row['album_id'] . '><img src="uploads/thumbs/' . $row['album_id'] . '/' . $row['album_id'] . '.' . $row['album_ext'] . '" />' . $row['album_name'] . '</a>';
}

sql=“从相册中选择*a.album\u id=i.album\u id，其中a.album\u id=”$相册编号；
$result=mysql\u查询（sql）；
while（$row=mysql\u fetch\u数组（$result））{
回声'；
}

---

然后，它应该准确地显示您希望它显示的内容

$albums\u query

没有img\u名称或ext字段。谢谢Patashu，非常简单，但我没有看到它。