Php Yii:无法在网格视图中列出数据
我不能使用yii框架在网格中列出数据。我的控制器是Sitecontroller.php,我的视图是list\u jobseker.php。我遇到错误“致命错误:调用非对象上的成员函数getData()”。有人帮我吗 我的控制器代码Php Yii:无法在网格视图中列出数据,php,yii,Php,Yii,我不能使用yii框架在网格中列出数据。我的控制器是Sitecontroller.php,我的视图是list\u jobseker.php。我遇到错误“致命错误:调用非对象上的成员函数getData()”。有人帮我吗 我的控制器代码 public function actionlist_jobseeker() { $session_id=Yii::app()->session['user_id']; if ($session_id == "") {
public function actionlist_jobseeker()
{
$session_id=Yii::app()->session['user_id'];
if ($session_id == "")
{
$this->redirect( array('/employee/site/login'));
}
$user_id =$session_id;
$models = Yii::app()->db->createCommand()
->select('*')
->from('job_seeker_profile s')
->join('job_profile j','s.user_id = j.user_id')
->order('s.id')
->queryAll();
$this->render('list_jobseeker',array('models' =>$models));
}
查看-list_jobseker.php
<h1>View Jobseeker</h1>
<div class="flash-success">
</div>
<div class="form">
<?php
$this->widget('zii.widgets.grid.CGridView', array(
'id'=>'rates-phase-grid',
'htmlOptions' => array('class' => 'table table-striped table-bordered table-hover'),
'dataProvider'=>new CArrayDataProvider($models),
'columns' => array(
array(
'name' => 'Name',
'type' => 'raw',
'value' => 'CHtml::encode($data[*]->name)',
'htmlOptions' => array('style'=>'width:90px;','class'=>'zzz'),
),
array(
'name' => 'Email',
'type' => 'raw',
'value' => 'CHtml::encode($data[*]->email)',
'htmlOptions' => array('style'=>'width:250px;','class'=>'zzz')
),
array(
'name' => 'Password',
'type' => 'raw',
'value' => 'CHtml::encode($data[*]->password)',
'htmlOptions' => array('style'=>'width:90px;','class'=>'zzz')
),
array(
'name' => 'Contact No',
'type' => 'raw',
'value' => 'CHtml::encode($data[*]->contact_no)',
'htmlOptions' => array('style'=>'width:40px;','class'=>'zzz')
),
array(
'name' => 'Gender',
'type' => 'raw',
'value' => 'CHtml::encode($data[*]->gender)',
'htmlOptions' => array('style'=>'width:40px;','class'=>'zzz')
),
array(
'class' =>'CButtonColumn',
'deleteConfirmation'=>'Are you sure you want to delte this item?',
'template'=>'{update}{delete}',
'buttons' =>array('update'=>array(
'label'=>'edit',
'url'=>'Yii::app()->controller->createUrl("UpdateJob",array("id"=>$data["id"]))',
),
'delete'=>array('label'=>'delete',
'url'=>'Yii::app()->controller->createUrl("DeleteJob",array("id"=>$data["id"]))'),
)
)
),
));
?>
查看求职者
dataProvider
应该是一个实例。您正在传入一个数组:$model
。您可以将其包装为:
其他几个问题:
a) gridview希望$data
是一个对象而不是数组。将所有$data->*
实例更改为$data[*]
或使用CActiveDataProvider
和CActiveRecord
实例作为求职者档案
表
b) 按照惯例,$model
通常指单个CModel
实例。因此,您的数组应以复数形式命名,例如$items
我使用以下名称:
$data = ...::model()->findAll();
$dataProvider=new CArrayDataProvider('Class of your object');
$dataProvider->setData($data);
$dataProvider->keyField = "primary key of your model";
$this->widget('zii.widgets.grid.CGridView', array(
'dataProvider'=>$dataProvider,
...
array( 'class'=>'CButtonColumn',
'template' => '{ver}',
'buttons' => array(
'ver' => array(
'url'=>'"?id=".$data["..."]',
'imageUrl'=> Yii::app()->baseUrl.'/images/view.png', //Image URL of the button.
),
)
),
您好,现在我遇到了错误“尝试获取非对象C:\wamp\www\yii\u new\framework\base\CComponent.php(612):eval()'d code(1)”您使用的网格错误。我添加了一些问题。在C:\wamp\www\yii\u new\framework\base\CComponent.php(612):eval()'d code on line 1)中出现错误“Parse error:syntax error,意外的'*',应为'].”此外,我已经编辑了视图和控制器页面,请查看。您还没有阅读手册。答案在评论中:和可能的重复
$data = ...::model()->findAll();
$dataProvider=new CArrayDataProvider('Class of your object');
$dataProvider->setData($data);
$dataProvider->keyField = "primary key of your model";
$this->widget('zii.widgets.grid.CGridView', array(
'dataProvider'=>$dataProvider,
...
array( 'class'=>'CButtonColumn',
'template' => '{ver}',
'buttons' => array(
'ver' => array(
'url'=>'"?id=".$data["..."]',
'imageUrl'=> Yii::app()->baseUrl.'/images/view.png', //Image URL of the button.
),
)
),