Php 尝试创建删除按钮以删除数据库中的记录
我正在做一个学校项目 这个项目的意义是我创建了一个Php 尝试创建删除按钮以删除数据库中的记录,php,html,sql,database,mysqli,Php,Html,Sql,Database,Mysqli,我正在做一个学校项目 这个项目的意义是我创建了一个登录/注册表单 在那里我可以注册,登录,查看记录 但我还需要制作一个下拉菜单,因为我可以看到所有记录(用户),在它下面我需要制作一个按钮,当我选择一个记录/用户并按下删除按钮时,它需要从数据库中删除。我不知道该怎么做 这是我的代码: <?php 创建一个按钮并将其命名为Delete <a class="delete" href="delete.php?id=<?php echo $row['id']; ?>">De
登录/注册表单
在那里我可以注册,登录,查看记录
但我还需要制作一个下拉菜单,因为我可以看到所有记录(用户),在它下面我需要制作一个按钮,当我选择一个记录/用户并按下删除按钮时,它需要从数据库中删除。我不知道该怎么做
这是我的代码:
<?php
创建一个按钮并将其命名为Delete
<a class="delete" href="delete.php?id=<?php echo $row['id']; ?>">Delete</a>
然后创建一个delete.php文件,并将这些代码放在那里
<?php include_once 'db_config_filename.php';
// get id value
$id = $_GET['id'];
// sql to delete a record
$sql = "DELETE FROM tablename WHERE id='$id'";
// print_r($sql);
if (mysqli_query($conn, $sql)) {
echo "Record deleted successfully";
}
else {
echo "Error deleting record: " . mysqli_error($conn);
}
//redirect here
include 'data.php';
?>
我几乎让它工作了。我现在有以下代码:
delete.php:
<?php
include ("connectie.php");
$sql = "SELECT * FROM users ";
$result = $conn->query($sql);
echo "<select name='user'>";
if ($result->num_rows>0) {
while($row = $result->fetch_assoc()) {
echo "<option value=" . $row['username'] . ">" . $row['username'] . "
</option>";
}
}
echo "</select>";
?>
<form action="" method="GET">
<input type="hidden" name="id" value=".$row['id']." />
<input type="submit" name="delete" value="verwijderen">
</form>
<?php
include ("deletecode.php");
?>
Deletecode.php:
<?php
$servername = "localhost";
$username = "student14_admin";
$password = "lol12345";
$dbname = "student14_jordi";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
// sql to delete a record
$sql = "DELETE FROM users WHERE id=3";
if (mysqli_query($conn, $sql)) {
echo "Record deleted successfully";
} else {
echo "Error deleting record: " . mysqli_error($conn);
}
mysqli_close($conn);
?>
delete.php:
Deletecode.php:
这只适用于记录3的课程。但现在我需要知道,如果我从下拉菜单中选择一条记录并单击删除按钮,它需要从我的数据库中删除该记录。我现在更新了代码,我还得到了一个额外的文件,用于解决删除代码语法问题,从id=$\u GET['id']的用户处删除;还是看不到所有的代码我找不到你抱歉我不明白那我该怎么办?因为现在什么都没用了
delete.php:
<?php
include ("connectie.php");
$sql = "SELECT * FROM users ";
$result = $conn->query($sql);
echo "<select name='user'>";
if ($result->num_rows>0) {
while($row = $result->fetch_assoc()) {
echo "<option value=" . $row['username'] . ">" . $row['username'] . "
</option>";
}
}
echo "</select>";
?>
<form action="" method="GET">
<input type="hidden" name="id" value=".$row['id']." />
<input type="submit" name="delete" value="verwijderen">
</form>
<?php
include ("deletecode.php");
?>
Deletecode.php:
<?php
$servername = "localhost";
$username = "student14_admin";
$password = "lol12345";
$dbname = "student14_jordi";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
// sql to delete a record
$sql = "DELETE FROM users WHERE id=3";
if (mysqli_query($conn, $sql)) {
echo "Record deleted successfully";
} else {
echo "Error deleting record: " . mysqli_error($conn);
}
mysqli_close($conn);
?>