Php 使用XPATH列出不包含内容的XML子元素名称

考虑以下简单的XML模式：

<products>
    <category name="furniture">
        <item name="chair">
            <size>
                <small>10</small>
                ...and many more
                <large>20</large>
            </size>
        </item>
    </category>
</products>

我正在寻找以下输出：

small
...rest of elements
large

---

Xpath表达式中有一些错误。第一个=位于错误位置，椅子字符串缺少结束引号。添加

/*

可以直接选择大小的子节点

/products/category[@name='furniture']/item[@name='chair']/size/*

使用DOMDocument的完整源代码：

$xml = <<<'XML'
  <products>
    <category name="furniture">
        <item name="chair">
            <size>
                <small>10</small>
                <large>20</large>
            </size>
        </item>
    </category>
  </products>
XML;

$dom = new DOMDocument();
$dom->loadXml($xml);
$xpath = new DOMXPath($dom);

$nodes = $xpath->evaluate("/products/category[@name='furniture']/item[@name='chair']/size/*");

foreach ($nodes as $node) {
  echo $node->localName, "\n";
}

$xml=localName，“\n”；
}

/products/category[@name='furniture']/item[@name='chair']/size/*

$xml = <<<'XML'
  <products>
    <category name="furniture">
        <item name="chair">
            <size>
                <small>10</small>
                <large>20</large>
            </size>
        </item>
    </category>
  </products>
XML;

$dom = new DOMDocument();
$dom->loadXml($xml);
$xpath = new DOMXPath($dom);

$nodes = $xpath->evaluate("/products/category[@name='furniture']/item[@name='chair']/size/*");

foreach ($nodes as $node) {
  echo $node->localName, "\n";
}