Php 仅获取相同的结果以显示在SQL中

这是我的代码，稍后我将把它放到php中，但目前我正在提供的查询测试程序中使用它。我们正在做凯文·培根的第一级而不是第六级

我的问题如下：

SELECT name,year
FROM actors
JOIN roles ON roles.actor_id = actors.id
JOIN movies ON movies.id=roles.movie_id
WHERE actors.first_name= 'kevin' AND actors.last_name='bacon' OR actors.first_name= 'sean' AND actors.last_name='penn'
ORDER BY movies.name;

Animal House 1978
Apollo 13 1995 
Few Good Men, A 1992 
Footloose 1984 
Hollow Man 2000 
JFK 1991 
Mystic River 2003 
Mystic River 2003 
Planes, Trains & Automobiles 1987 
Stir of Echoes 1999 

结果是

SELECT name,year
FROM actors
JOIN roles ON roles.actor_id = actors.id
JOIN movies ON movies.id=roles.movie_id
WHERE actors.first_name= 'kevin' AND actors.last_name='bacon' OR actors.first_name= 'sean' AND actors.last_name='penn'
ORDER BY movies.name;

Animal House 1978
Apollo 13 1995 
Few Good Men, A 1992 
Footloose 1984 
Hollow Man 2000 
JFK 1991 
Mystic River 2003 
Mystic River 2003 
Planes, Trains & Automobiles 1987 
Stir of Echoes 1999 

如何让它只显示神秘河？试试这个

SELECT DISTINCT name,year
FROM actors
JOIN roles ON roles.actor_id = actors.id
JOIN movies ON movies.id=roles.movie_id
WHERE actors.first_name= 'kevin' AND actors.last_name='bacon' OR actors.first_name= 'sean' AND actors.last_name='penn'
ORDER BY movies.name;

SELECT DISTINCT name,year
FROM actors
JOIN roles ON roles.actor_id = actors.id
JOIN movies ON movies.id=roles.movie_id
WHERE (actors.first_name= 'kevin' AND actors.last_name='bacon') OR (actors.first_name= 'sean' AND actors.last_name='penn')
ORDER BY movies.name;

试试这个

SELECT DISTINCT name,year
FROM actors
JOIN roles ON roles.actor_id = actors.id
JOIN movies ON movies.id=roles.movie_id
WHERE actors.first_name= 'kevin' AND actors.last_name='bacon' OR actors.first_name= 'sean' AND actors.last_name='penn'
ORDER BY movies.name;

SELECT DISTINCT name,year
FROM actors
JOIN roles ON roles.actor_id = actors.id
JOIN movies ON movies.id=roles.movie_id
WHERE (actors.first_name= 'kevin' AND actors.last_name='bacon') OR (actors.first_name= 'sean' AND actors.last_name='penn')
ORDER BY movies.name;

---

首先，将条件分组

WHERE (actors.first_name= 'kevin' AND actors.last_name='bacon') OR 
      (actors.first_name= 'sean' AND actors.last_name='penn')

其次，在

SELECT

关键字后添加

DISTINCT

SELECT DISTINCT ...

---

后续问题：为什么您只想显示

神秘河？
首先，对条件进行分组

WHERE (actors.first_name= 'kevin' AND actors.last_name='bacon') OR 
      (actors.first_name= 'sean' AND actors.last_name='penn')

其次，在
SELECT
关键字后添加
DISTINCT

SELECT DISTINCT ...

后续问题：为什么你只想展示
神秘河？
我认为你在这里要求的是不同的

DISTINCT关键字只能用于返回不同（不同）的值

试试这个

SELECT DISTINCT name,year
FROM actors
JOIN roles ON roles.actor_id = actors.id
JOIN movies ON movies.id=roles.movie_id
WHERE actors.first_name= 'kevin' AND actors.last_name='bacon' OR actors.first_name= 'sean' AND actors.last_name='penn'
ORDER BY movies.name;

SELECT DISTINCT name,year
FROM actors
JOIN roles ON roles.actor_id = actors.id
JOIN movies ON movies.id=roles.movie_id
WHERE (actors.first_name= 'kevin' AND actors.last_name='bacon') OR (actors.first_name= 'sean' AND actors.last_name='penn')
ORDER BY movies.name;

在where条款中

 WHERE (actors.first_name= 'kevin' AND actors.last_name='bacon') AND (actors.first_name= 'sean' AND actors.last_name='penn')

如果你想知道凯文·培根和肖恩·潘在同一部电影中的位置
我想你要的是不同的

DISTINCT关键字只能用于返回不同（不同）的值

试试这个

SELECT DISTINCT name,year
FROM actors
JOIN roles ON roles.actor_id = actors.id
JOIN movies ON movies.id=roles.movie_id
WHERE actors.first_name= 'kevin' AND actors.last_name='bacon' OR actors.first_name= 'sean' AND actors.last_name='penn'
ORDER BY movies.name;

SELECT DISTINCT name,year
FROM actors
JOIN roles ON roles.actor_id = actors.id
JOIN movies ON movies.id=roles.movie_id
WHERE (actors.first_name= 'kevin' AND actors.last_name='bacon') OR (actors.first_name= 'sean' AND actors.last_name='penn')
ORDER BY movies.name;

在where条款中

 WHERE (actors.first_name= 'kevin' AND actors.last_name='bacon') AND (actors.first_name= 'sean' AND actors.last_name='penn')

如果您想知道Kevin Bacon和Sean Penn在同一部电影中的位置
如果我正确理解了您的问题，您将尝试查找包含Sean Penn
和Kevin Bacon

的电影列表。如果是这样，那么您需要在查询中使用actors和roles表两次

SELECT
    movies.name,
    movies.year
FROM
    actors AS actor2 INNER JOIN roles AS role2 ON actor2.ID = role2.actor_id
           INNER JOIN actors AS actor1 INNER JOIN roles AS role1 ON actor1.ID = role1.actor_id
                INNER JOIN movies ON role1.movie_id = movies.ID ON role2.movie_id = movies.ID
WHERE
    actor1.first_name= 'kevin' AND actor1.last_name='bacon'
        AND
    actor2.first_name= 'sean' AND actor2.last_name='penn'
ORDER BY movies.name;

---

如果我正确理解了你的问题，那么你是在试图找到包含肖恩·潘（Sean Penn）和凯文·培根（Kevin Bacon）的电影列表。如果是这样，那么您需要在查询中使用actors和roles表两次

SELECT
    movies.name,
    movies.year
FROM
    actors AS actor2 INNER JOIN roles AS role2 ON actor2.ID = role2.actor_id
           INNER JOIN actors AS actor1 INNER JOIN roles AS role1 ON actor1.ID = role1.actor_id
                INNER JOIN movies ON role1.movie_id = movies.ID ON role2.movie_id = movies.ID
WHERE
    actor1.first_name= 'kevin' AND actor1.last_name='bacon'
        AND
    actor2.first_name= 'sean' AND actor2.last_name='penn'
ORDER BY movies.name;

---

你想知道凯文·培根和肖恩·潘在同一部电影中的位置，对吗？你想知道凯文·培根和肖恩·潘在同一部电影中的位置，对吗？