Php 将表单数据传递到下一页时出现会话错误
我正在使用session将表单数据传递到下一页,但我不断出错。下面是我得到的错误 警告:session\u start():无法发送会话cookie-已由(输出从C:\xampp\htdocs\KBSS\u PerformanceApparialSystem\individual\u review2.php:202)在C:\xampp\htdocs\KBSS\u PerformanceApparialSystem\individual\u review2.php第205行的C:\xampp\htdocs\KBSS\u PerformanceApparialSystem\individual\u review2.php中发送的标头 警告:session\u start():无法发送会话缓存限制器-标题已发送(输出开始于C:\xampp\htdocs\KBSS\u PerformanceApparialSystem\individual\u review2.php:202),位于C:\xampp\htdocs\KBSS\u PerformanceApparialSystem\individual\u review2.php的第205行 致命错误:在中调用未定义的函数session_register() 这是我的密码:Php 将表单数据传递到下一页时出现会话错误,php,Php,我正在使用session将表单数据传递到下一页,但我不断出错。下面是我得到的错误 警告:session\u start():无法发送会话cookie-已由(输出从C:\xampp\htdocs\KBSS\u PerformanceApparialSystem\individual\u review2.php:202)在C:\xampp\htdocs\KBSS\u PerformanceApparialSystem\individual\u review2.php第205行的C:\xampp\ht
<php
session_start();
session_register('f_name');
session_register('s_name');
session_register('employee_id_number');
session_register('department');
session_register('supervisors_name');
session_register('position');
session_register('review_date');
session_register('duties');
session_register('kpi');
//finally, let's store our posted values in the session variables
$_SESSION['f_name'] = $_POST['f_name'];
$_SESSION['s_name'] = $_POST['s_name'];
$_SESSION['employee_id_number'] = $_POST['employee_id_number'];
$_SESSION['department'] = $_POST['department'];
$_SESSION['supervisors_name'] = $_POST['supervisors_name'];
$_SESSION['position'] = $_POST['position'];
$_SESSION['review_date'] = $_POST['review_date'];
$_SESSION['duties'] = $_POST['duties'];
$_SESSION['kpi'] = $_POST['kpi'];
?>
从开始,不是吗从改变开始