Php 如果其中一列与Sql server相同,则删除重复行
我有一个查询,它链接表1和表2,并获取表1中结果的最后一条注释,这是有效的,但是当表1中有多条记录具有相同的ID时,例如,它再次显示结果,这里就是一个示例 查询结果Php 如果其中一列与Sql server相同,则删除重复行,php,sql-server,Php,Sql Server,我有一个查询,它链接表1和表2,并获取表1中结果的最后一条注释,这是有效的,但是当表1中有多条记录具有相同的ID时,例如,它再次显示结果,这里就是一个示例 查询结果 ID | Machine | description | createdtime | product code | work order | qty | comment | Reson No 129 |1 | A name | 2015-01-08 07:38:41.427 | A code | 12
ID | Machine | description | createdtime | product code | work order | qty | comment | Reson
No
129 |1 | A name | 2015-01-08 07:38:41.427 | A code | 12/14/0038 | 4000 | comment | Reason
143 |1 | A name | 2015-01-08 13:30:39.403 | A code | 12/14/0038 | 4000 | comment | Reson
130 |4 | A name | 2015-01-08 07:38:46.540 | A code | 12/14/0045 | 12000 | comment | Reason
131 |5 | A name | 2015-01-08 07:38:50.243 | A code | 01/15/0001 | 4000 | comment | Reason
如您所见,这里有两条记录,机器编号为1,一条在上午创建,另一条在中午后创建,但是我只希望显示最新的一条,这是我的查询
SELECT Qualitycontrol.ID, Qualitycontrol.MachineNo, Qualitycontrol.Description, Qualitycontrol.CreatedTime, Qualitycontrol.ProductCode, Qualitycontrol.WorkOrder,
Qualitycontrol.Quantity, Qc.Comment, Qc.Reason
FROM Qualitycontrol
OUTER APPLY (
SELECT TOP 1 *
FROM QualityControl_Comments
WHERE Qualitycontrol.ID = QCUID
ORDER BY Qualitycontrol.ID DESC -- whatevet defines order in QualityControl_Comments
) AS Qc
WHERE (Qualitycontrol.CreatedTime BETWEEN CAST(GETDATE() AS DATE) AND DATEADD(DAY, 1, CAST(GETDATE() AS DATE)))
ORDER BY Qualitycontrol.MachineNo
你可以用这样的东西。 使用row_number,您可以按machineine id对数据进行分区,并按日期对数字进行排序。你可以用一个简单的where-clouse来选择你想要的
;WITH CTE
as
(
SELECT Qualitycontrol.ID, Qualitycontrol.MachineNo, Qualitycontrol.Description, Qualitycontrol.CreatedTime, Qualitycontrol.ProductCode, Qualitycontrol.WorkOrder,
Qualitycontrol.Quantity, Qc.Comment, Qc.Reason
FROM Qualitycontrol
OUTER APPLY (
SELECT TOP 1 *
FROM QualityControl_Comments
WHERE Qualitycontrol.ID = QCUID
) AS Qc
WHERE (Qualitycontrol.CreatedTime BETWEEN CAST(GETDATE() AS DATE) AND DATEADD(DAY, 1, CAST(GETDATE() AS DATE)))
), CTE2 as
(
select *, row_number() over(partition by MachineNo order by CreatedTime desc) as 'row_index' from cte
)
select * from cte2
where row_index = 1
order by MachineNo
也许像这样的事情会奏效
SELECT Qualitycontrol.ID, Qualitycontrol.MachineNo, Qualitycontrol.Description, Qualitycontrol.CreatedTime, Qualitycontrol.ProductCode, Qualitycontrol.WorkOrder,
Qualitycontrol.Quantity, Qc.Comment, Qc.Reason
FROM Qualitycontrol
OUTER APPLY (
SELECT TOP 1 *
FROM QualityControl_Comments
WHERE Qualitycontrol.ID = QualityControl_Comments.QCUID
ORDER BY Qualitycontrol.ID DESC -- whatevet defines order in QualityControl_Comments
) AS Qc
INNER JOIN
(
SELECT Qualitycontrol.MachineNo, MAX(Qualitycontrol.ID) MID
FROM Qualitycontrol
GROUP BY Qualitycontrol.MachineNo
) UNQ ON UNQ.MID = Qualitycontrol.ID
WHERE (Qualitycontrol.CreatedTime BETWEEN CAST(GETDATE() AS DATE) AND DATEADD(DAY, 1, CAST(GETDATE() AS DATE)))
ORDER BY Qualitycontrol.MachineNo
嘿,我得到这些错误消息4104,16级,状态1,第17行,多部分标识符“Qualitycontrol.MachineNo”无法绑定。Msg 4104,级别16,状态1,第17行无法绑定多部分标识符“Qualitycontrol.CreatedTime”。请立即尝试,我无法测试查询,但请立即尝试。我已经更新了答案是的,当我在Microsoft sql server management studio中运行查询时,这是有效的,但是当我在php中使用它时,它不会返回任何东西。你知道为什么会这样吗?我不知道,我对php没有过期性,但是你可以使用视图-只需使用此查询创建视图(或过程等)。您应始终在应用程序中使用视图,而不应仅在应用程序代码中使用表。请尝试完全限定QCUID,即在外部应用范围中使用QualityControl_Comments.QCUID。否则我看不出这有什么问题问题,问题是它正在拉取当天的所有记录,但是我只想要当天的最新记录,关于评论表的部分是fineAh,我的不好。这可能会帮助您: