奇怪的未定义变量php错误

我正在使用PHP OOP开发CMS。在这个CMS中，有一个功能，一个网站的管理员可以添加另一个管理员。为此，我创建了一个表单并添加了操作。该文件名为

admin\u new.php

，如下所示：

    <?php 
if (isset($_POST['submit'])){
    $username = $_POST['uname'];
    $email = $_POST['email'];
    $password = $_POST['pass'];
    $groups = $_POST['groups'];
    if($groups == "Main Admin"){
        $level = 1;
    }else if($groups == "Administrator"){
        $level = 2;
    }else if($groups == "Content Creator"){
        $level = 3;
    }else if($groups == "Social Media Manager"){
        $level = 4;
    }else{
        $level = 5;
    }
    if (filter_var($email, FILTER_VALIDATE_EMAIL) === false) {
        $notice['email_validation'] = "The email that you have entered is not a valid one";
    }else{
        $registration = new Register();
        $notice = $registration->CheckUname($username,$email,$password,$groups‌​,$level);
    }   
}
?>
<div class="content-wrapper">
    <section class="content-header">
        <h1>
            Add New Admin
            <small>You can add new admin here</small>
        </h1>
        <ol class="breadcrumb">
            <li class="active">addnewadmin.php</li>
        </ol>
    </section>
    <section class="content">
        <div class="row">
            <div class="col-md-6">
                <div class="box box-primary">
                    <div class="box-header with-border">
                        <h3 class="box-title">Required Information</h3>
                    </div>
                    <?php 
                    if(isset($notice['email_validation'])) {
                        echo "
                            <div class='alert alert-danger'>
                                <strong>Hey!</strong> ".$notice['email_validation'].".
                            </div>
                        ";
                    }
                    if(isset($notice['username_exists'])) {
                        echo "
                            <div class='alert alert-danger'>
                                <strong>Hey!</strong> ".$notice['username_exists'].".
                            </div>
                        ";
                    }
                    if(isset($notice['email_exists'])) {
                        echo "
                            <div class='alert alert-danger'>
                                <strong>Hey!</strong> ".$notice['email_exists'].".
                            </div>
                        ";
                    }
                    if(isset($notice['success_message'])) {
                        echo "
                            <div class='alert alert-success'>
                                <strong>Hey!</strong> ".$notice['success_message'].".
                            </div>
                        ";
                    }
                    ?>
                    <form role="form" method="POST" action="">
                        <div class="box-body">
                            <div class="form-group">
                                <label>User name</label>
                                <input type="text" class="form-control" placeholder="Enter username" name="uname" required>
                            </div>
                            <div class="form-group">
                                <label for="exampleInputEmail1">Email address</label>
                                <input type="email" class="form-control" id="exampleInputEmail1" placeholder="Enter email" name="email" required>
                            </div>
                            <div class="form-group">
                                <label for="exampleInputPassword1">Temporary password</label>
                                <input type="password" class="form-control" id="exampleInputPassword1" placeholder="Enter password" name="pass" required>
                            </div>
                            <div class="form-group">
                                <label>Group admin</label>
                                <select class="form-control" name="groups">
                                    <option value="Main Admin">Main Admin</option>
                                    <option value="Administrator">Administrator</option>
                                    <option value="Content Creator">Content Creator</option>
                                    <option value="Social Media Manager">Social Media Manager</option>
                                    <option value="Analyst">Analyst</option>
                                </select>
                            </div>
                        </div>
                        <div class="box-footer">
                            Visit <a href="https://zite.pouyavagefi.com/documentation/types.php">admin types</a> documentation to know the differences between each admin.
                        </div>
                        <div class="box-footer">
                            <button name="submit" type="submit" class="btn btn-primary">Submit</button>
                        </div>
                    </form>
                </div>
            </div>
        </div>
    </section>
</div>

您可以在代码中看到，我已经定义了$groups变量，它在表单中获得了groups值。所以我真的不知道为什么我会犯这个错误

---

所以，如果你知道我该做什么或者我的错在哪里，请告诉我。。我真的很感激。感谢您在下面的函数中使用了

$groups1

而不是

$groups

>更新为

$groups

public function NewAdmin($username,$email,$password,$groups,$level)
    {
        if(!empty($username)&&!empty($email)&&!empty($password)&&!empty($groups)&&!empty($level))
        {
            $reg = $this->db->prepare("INSERT INTO admins (user_name, email_address, password_hash, group_admin, date_joined, admin_level) VALUES ( ?, ?, ?, ?, NOW(), ?)");
            $reg->bindParam(1,$username);
            $reg->bindParam(2,$email);
            $reg->bindParam(3,$password);
            $reg->bindParam(4,$groups1);
            $reg->bindParam(5,$level);
            $reg->execute();
        }
    }

---

由于$groups在调用中，您将遇到此错误

$notice = $registration->CheckUname($username,$email,$password,$groups‌​‌​,$level); 

$groups

以不同的编码编写，并且具有非ASCII字符。可能有一个或多个字母是用不同的语言打印的。只需用普通的拉丁语输入，或者从上面的一个变量复制过来。 这应该可以解决问题

编辑：

---

除了未来的问题外，如果您偶然发现类似问题，只需将代码转换为ASCII编码并返回UTF-8，所有非ASCII字符将被替换为一些通用替换，如下划线或问号

您是否尝试输出每个变量以检查它们是否包含某些内容并从中开始？不过，还有一件事，与此错误不同的是，您永远不会将

$this->notice

返回为空，因为您声明

$notice

而不是

$this->notice['param']='arg'

伙计们，您可以将注释作为答案来写吗！！我不明白你在这个评论部分所说的是什么，为什么不在你的回答中进行更正呢？那只是为了测试问题。。现在，问题已更新，问题已显示，以检查其是否为非ascii或not@chris85，请尝试复制粘贴此处的部分代码：您能提供一些有关您所说内容的参考资料或文章吗？啊，我知道，有尾随内容。@wrephebiajou在

$groups

之后和

之前，

您有一个非ascii字符。

public function NewAdmin($username,$email,$password,$groups,$level)
    {
        if(!empty($username)&&!empty($email)&&!empty($password)&&!empty($groups)&&!empty($level))
        {
            $reg = $this->db->prepare("INSERT INTO admins (user_name, email_address, password_hash, group_admin, date_joined, admin_level) VALUES ( ?, ?, ?, ?, NOW(), ?)");
            $reg->bindParam(1,$username);
            $reg->bindParam(2,$email);
            $reg->bindParam(3,$password);
            $reg->bindParam(4,$groups1);
            $reg->bindParam(5,$level);
            $reg->execute();
        }
    }

$notice = $registration->CheckUname($username,$email,$password,$groups‌​‌​,$level);