Php MYSQL或一列上的两个值

我有两张桌子

表1:tA

表2：结核病

预期产量

mysql代码：

我的mysql代码的结果：

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怎么办？

按tA_id删除您的组，因为它将cat_name Mobile和其他手机分组在一起

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如果您需要按tB.cat_id ASC使用订单，我相信它将显示您需要的cat_id 1和2

查询中有错误。。。缺少JOIN

查询 这正在获取预期的结果

+----+---------------------+-----+--------+--------+----------+
| id |  url                |  id |  tA_id | cat_id | cat_name |
+----+---------------------+-----+--------+--------+----------+
| 1  | hxxp://www.aaa.com  |  1  |   1    |  1     |   mobile |
| 2  | hxxp://www.bbb.com  |  3  |   2    |  2     |   other  |
+----+---------------------+-----+--------+--------+----------+

试试这个：-

select * 
from tA 
inner join tB 
on tA.id = tB.tA_id 
where tB.cat_id = 1 
or tB.cat_id = 2 
group by tb.cat_name;

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希望它能帮助您。

但我的数据库中有300多条记录。如果我使用“按类别名称分组”。我的结果显示了2条记录。请尝试按类别名称分组。

+----+-------+--------+----------+
| id | tA_id | cat_id | cat_name |
+----+-------+--------+----------+
| 1  |   1   |    1   |   Mobile |
| 3  |   2   |    2   |   Other  |
+----+-------+--------+----------+

select * 
from tA 
inner tB 
on tA.id = tB.tA_id 
where tB.cat_id = 1 
or tB.cat_id = 2 
Group By tA_id

+----+-------+--------+----------+
| id | tA_id | cat_id | cat_name |
+----+-------+--------+----------+
| 1  |   1   |   2    |   Other  |
| 3  |   2   |   2    |   Other  |
+----+-------+--------+----------+

SELECT * 
FROM tA 
INNER JOIN tB 
ON tA.id = tB.tA_id 
WHERE tB.cat_id = 1 
OR tB.cat_id = 2 
GROUP BY tA_id

+----+---------------------+-----+--------+--------+----------+
| id |  url                |  id |  tA_id | cat_id | cat_name |
+----+---------------------+-----+--------+--------+----------+
| 1  | hxxp://www.aaa.com  |  1  |   1    |  1     |   mobile |
| 2  | hxxp://www.bbb.com  |  3  |   2    |  2     |   other  |
+----+---------------------+-----+--------+--------+----------+

select * 
from tA 
inner join tB 
on tA.id = tB.tA_id 
where tB.cat_id = 1 
or tB.cat_id = 2 
group by tb.cat_name;