计算sql结果中的重复项并用PHP显示

我试图从MySQL表中检索引用URL的列表（列

referer

）。

referer

列多次包含相同的URL，我想计算并打印URL出现的次数。然后按降序打印计数

我有下面的代码，但显然是错误的地方

$ref=$icdb->get_row("SELECT COUNT(referrer) AS frequency, referrer FROM url_log WHERE u = '".$dom."' GROUP BY referrer ORDER BY frequency DESC");


foreach ($ref as $details) {
   echo "<td>".$details['referrer']."</td><td>".$details['frequency']."</td>";
}

foreach声明给了我：

---

我想你的问题在于计数（1）。

---

我建议将其更改为COUNT（referer）。

对我来说不明显：-（最好能帮助我们，提供一些样本数据。或Fiddle查看上面的编辑@echo_MeI获得以下信息：3 3 h hi在代码中找不到任何其他错误。您的问题出在其他地方。

$url_log = array(
  array('id' => '681','url_id' => '69','options' => '','created_day' => '20140128','created' => '1390945235','deleted' => '0','u' => 'rch.metwitter','referrer' => 'http://www.domain.com/','ipaddr' => '121.223.91.20','browser' => 'Mozilla/5.0 (Windows NT 6.1; WOW64; Trident/7.0; rv:11.0) like Gecko'),
  array('id' => '685','url_id' => '69','options' => '','created_day' => '20140130','created' => '1391115029','deleted' => '0','u' => 'rch.metwitter','referrer' => 'http://www.domain.com/?page=custom&id=69','ipaddr' => '121.223.91.20','browser' => 'Mozilla/5.0 (Windows NT 6.1; WOW64; Trident/7.0; rv:11.0) like Gecko'),
  array('id' => '686','url_id' => '69','options' => '','created_day' => '20140130','created' => '1391116005','deleted' => '0','u' => 'rch.metwitter','referrer' => 'http://www.domain.com/','ipaddr' => '121.223.91.20','browser' => 'Mozilla/5.0 (Windows NT 6.1; WOW64; Trident/7.0; rv:11.0) like Gecko')
);