Php 提取前打印数据

下面是我的代码

<?php
            if(isset($_POST['Generate']))
            {
                $emp = mysql_real_escape_string($_POST['employee']);
                $startD = $_POST['from'];
                $endD = $_POST['to'];
                $search = "SELECT leaveregister.*, users.first_name, users.last_name FROM leaveregister INNER JOIN users ON leaveregister.employee=users.id WHERE employee = '$emp' AND startDate >= '$startD' AND endDate <= '$endD'";
                $dosearch = mysql_query($search);
                if(mysql_num_rows($dosearch) > 0)
                {
                    echo '<span>Employee : <strong>'.$row['first_name'].'</strong></span>&nbsp;&nbsp;&nbsp;<span>From : <strong>'.$startD.'</strong></span>&nbsp;&nbsp;&nbsp;<span>To : <strong>'.$endD.'</strong></span><br><br><br>' ;
                    echo '<table border="1" class="table table-bordered">';
                    echo '<thead><th>Emp</th><th>Leave Type</th><th>Leave Duration</th><th>Start</th><th>End</th><th>Remarks</th></thead>';
                    echo '<tbody>';
                    while($row = mysql_fetch_array($dosearch))
                    {
                        echo '<tr><td>'.$row['employee'].'</td><td>'.$row['leaveType'].'</td><td>'.$row['leaveDays'].'</td><td>'.$row['startDate'].'</td><td>'.$row['endDate'].'</td><td>'.$row['remarks'].'</td></tr>';
                        }
                    echo '</tbody></table>';
                    }
                    else
                    {                       
                    echo "Not Found!!";
                    }
                }
        ?>

我知道我不能在那里使用

$row

---

那我怎么打印呢？

你可以像这样使用代码。。。您需要使用两个while循环，这样就可以使用

mysql\u data\u seek（）

函数重置第一个循环并正常运行第二个循环…我对mysql的建议不适合尝试使用MySqli

if(isset($_POST['Generate']))
    {
        $emp = mysql_real_escape_string($_POST['employee']);
        $startD = $_POST['from'];
        $endD = $_POST['to'];
        $search = "SELECT leaveregister.*, users.first_name, users.last_name FROM leaveregister INNER JOIN users ON leaveregister.employee=users.id WHERE employee = '$emp' AND startDate >= '$startD' AND endDate <= '$endD'";
        $dosearch = mysql_query($search);
        if(mysql_num_rows($dosearch) > 0)
        {
            while($rows = mysql_fetch_assoc($dosearch)){
             $name = $rows['first_name'];
            }
            echo '<span>Employee : <strong>'.$name.'</strong></span>&nbsp;&nbsp;&nbsp;<span>From : <strong>'.$startD.'</strong></span>&nbsp;&nbsp;&nbsp;<span>To : <strong>'.$endD.'</strong></span><br><br><br>' ;
            echo '<table border="1" class="table table-bordered">';
            echo '<thead><th>Emp</th><th>Leave Type</th><th>Leave Duration</th><th>Start</th><th>End</th><th>Remarks</th></thead>';
            echo '<tbody>';
            mysql_data_seek($dosearch, 0);
            while($row = mysql_fetch_array($dosearch))
            {
                echo '<tr><td>'.$row['employee'].'</td><td>'.$row['leaveType'].'</td><td>'.$row['leaveDays'].'</td><td>'.$row['startDate'].'</td><td>'.$row['endDate'].'</td><td>'.$row['remarks'].'</td></tr>';
                }
            echo '</tbody></table>';
            }
            else
            {                       
            echo "Not Found!!";
            }
        }

if（isset（$\u POST['Generate']））
{
$emp=mysql\u real\u escape\u字符串（$\u POST['employee']）；
$startD=$_POST['from']；
$endD=$_POST['to']；
$search="选择LeVerierister.*，UsR.FrestTyNo.U.S.ListTyNeNe:从LeeReavigister.Enger-Users.ID中的LeaErristerEnter用户，其中雇员=“$EMP”和StaseDea> =“$STARDD”，并且结束日期<代码> MySQL<构造函数是，并且是直截了当的。请考虑切换到“或者”，以确保您还用于防止SQL注入：听起来你在寻找表中的一个或两个单独的查询。虽然我不能真正推荐如何使用MySQL，因为它会让你暴露严重的安全漏洞，因此这样做是不道德的。相反，我建议用MySQLi或PDO重新编写代码。这只需要一秒钟，而且会真正帮助你从长远来看：）我已经试过了。
$name
打印成功。但是第二个
在
不起作用时什么也不打印。你能解释一下如何使用
mysql\u data\u seek
？我添加了那段代码。你也尝试过这一行之前的
mysql\u data\u seek（$dosearch，0）
，而（$row=mysql\u fetch\u array（$dosearch））

。再次检查变量名

$row

是否与两个变量的名称不同，谢谢Nawin。已解决。

if(isset($_POST['Generate']))
    {
        $emp = mysql_real_escape_string($_POST['employee']);
        $startD = $_POST['from'];
        $endD = $_POST['to'];
        $search = "SELECT leaveregister.*, users.first_name, users.last_name FROM leaveregister INNER JOIN users ON leaveregister.employee=users.id WHERE employee = '$emp' AND startDate >= '$startD' AND endDate <= '$endD'";
        $dosearch = mysql_query($search);
        if(mysql_num_rows($dosearch) > 0)
        {
            while($rows = mysql_fetch_assoc($dosearch)){
             $name = $rows['first_name'];
            }
            echo '<span>Employee : <strong>'.$name.'</strong></span>&nbsp;&nbsp;&nbsp;<span>From : <strong>'.$startD.'</strong></span>&nbsp;&nbsp;&nbsp;<span>To : <strong>'.$endD.'</strong></span><br><br><br>' ;
            echo '<table border="1" class="table table-bordered">';
            echo '<thead><th>Emp</th><th>Leave Type</th><th>Leave Duration</th><th>Start</th><th>End</th><th>Remarks</th></thead>';
            echo '<tbody>';
            mysql_data_seek($dosearch, 0);
            while($row = mysql_fetch_array($dosearch))
            {
                echo '<tr><td>'.$row['employee'].'</td><td>'.$row['leaveType'].'</td><td>'.$row['leaveDays'].'</td><td>'.$row['startDate'].'</td><td>'.$row['endDate'].'</td><td>'.$row['remarks'].'</td></tr>';
                }
            echo '</tbody></table>';
            }
            else
            {                       
            echo "Not Found!!";
            }
        }