Php 根据值更改td等级?
我在表中有行,我想根据值更改某些元素的类。我现在所拥有的:Php 根据值更改td等级?,php,html,css,if-statement,tablerow,Php,Html,Css,If Statement,Tablerow,我在表中有行,我想根据值更改某些元素的类。我现在所拥有的: <td><span class="label label-warning">".$rows["riskScoreText"]."</span></td> “$rows[“riskScoreText”]” 如果“riskScoreText”的值为“高”,则应具有警告类标签 如果“riskScoreText”的值为“Low”,则应具有标签成功类 我将如何做到这一点 根据额外的引号,我假
<td><span class="label label-warning">".$rows["riskScoreText"]."</span></td>
“$rows[“riskScoreText”]”
- 如果“riskScoreText”的值为“高”,则应具有警告类标签
- 如果“riskScoreText”的值为“Low”,则应具有标签成功类
我将如何做到这一点 根据额外的引号,我假设您已经从现有的回音中提取了这个。所以它看起来像:
echo '<td><span class="label ';
if($rows["riskScoreText"] == 'High'){ echo "label-warning"; }
elseif($rows["riskScoreText"] == 'Low'){ echo "label-success"; }
echo '">'.$rows["riskScoreText"].'</span></td>';
echo'.$rows[“riskScoreText”].';
基于额外的引号,我假设您已经从现有的回音中提取了这个。所以它看起来像:
echo '<td><span class="label ';
if($rows["riskScoreText"] == 'High'){ echo "label-warning"; }
elseif($rows["riskScoreText"] == 'Low'){ echo "label-success"; }
echo '">'.$rows["riskScoreText"].'</span></td>';
echo'.$rows[“riskScoreText”].';
试试这个:
$value = $rows["riskScoreText"];
if($value == 'High') {
$class = "label label-warning";
} else {
$class = "label label-low"; }
<td><span class="<?php echo $class>">".$rows["riskScoreText"]."</span></td>
$value=$rows[“riskScoreText”];
如果($value=='High'){
$class=“标签警告”;
}否则{
$class=“标签低”;}
试试这个:
$value = $rows["riskScoreText"];
if($value == 'High') {
$class = "label label-warning";
} else {
$class = "label label-low"; }
<td><span class="<?php echo $class>">".$rows["riskScoreText"]."</span></td>
$value=$rows[“riskScoreText”];
如果($value=='High'){
$class=“标签警告”;
}否则{
$class=“标签低”;}
假设你在运行一个循环
<?php
foreach( $array as $rows ) {
if( $rows["riskScoreText"] == "High" ) {
$class = " label-warning";
} elseif( $rows["riskScoreText"] == "Low" ) {
$class = " label-success";
} else {
$class = ""; //NO STYLE?
}
?>
<td><span class="label<?php echo $class; ?>"><?php echo $rows["riskScoreText"]; ?></span></td>
<?php
}
?>
假设你在运行一个循环
<?php
foreach( $array as $rows ) {
if( $rows["riskScoreText"] == "High" ) {
$class = " label-warning";
} elseif( $rows["riskScoreText"] == "Low" ) {
$class = " label-success";
} else {
$class = ""; //NO STYLE?
}
?>
<td><span class="label<?php echo $class; ?>"><?php echo $rows["riskScoreText"]; ?></span></td>
<?php
}
?>
没有javascript?这是由服务器(PHP,JSP)还是客户端(javascript,jQuery)技术输出?PHP驱动输出。没有javascript?这是由服务器(PHP,JSP)还是客户端(javascript,jQuery)技术输出?PHP驱动输出。